VD2p11 1701 Csaba Molnar Ride Comfort
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Transcript of VD2p11 1701 Csaba Molnar Ride Comfort
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kN 1000newton ora 3600sec
v 40kmora
viteza de deplasare
d 2m d 2 m Lungimea de unda a denivelarii cosinusoidale
h0 2cm Inaltimea denivelarii cosinusoidale
mtot 553.1kgmb 0.93 mtot mb 514.383 kg Masa suspendata
mw mtot mb mw 38.717 kg Masa nesuspendata
kt 210kNm
Rigiditatea pneului
ks 29kNm
Rigiditatea arcului
ct 0.18kN secm
Coeficientul de amortizareal pneului
ct 0.1kN secm
cs 2.5kN secm
Coeficientul de amortizare al amortizorului
bksmb
b 7.509radsec
Pulsatia proprie neamortizata inferioara (acaroseriei)
fbb
2 rad fb 1.2 Hz Frecventa proprie neamortizata inferioara(acaroseriei)
wktmw
w 73.648radsec
Pulsatia proprie neamortizata inferioara (a rotii)
fww
2 rad fw 11.72 Hz Frecventa proprie neamortizata superioara (a rotii)
k1
1kt
1ks
k 25.481 kN
m Rigiditatea echivalenta a suspensiei
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c1
1ct
1cs
c 0.096 kN m
s
1
Coeficientul de amortizare echivalent alsuspensiei
Ecuatiile de miscare i 1
mbd2
dt2zb cs
ddt
zwddt
zb ks zw zb =
mwd2
dt2zw ct
ddt
h ddt
zw kt h zw cs ddt zw ddt zb ks zw zb =
mbd2
dt2zb cs
ddt
zb ks zb csddt
zw ks zw=
mwd2
dt2zw ct cs ddt zw kt ks zw ct ddt h kt h cs ddt zb ks zb=
2 mb zb i cs zb ks zb i cs zw ks zw=
2 mw zw i ct cs zw kt ks zw i ct h kt h i cs zb ks zb=
2 mb i cs ks zb i cs ks zw=
2 mw i ct cs kt ks zw i ct kt h i cs ks zb=
zw2 mb i cs ksi cs ks
zb=
2 mw i ct cs kt ks
2 mb i cs ksi cs ks
i cs ks
zb i ct kt h=
zbi cs ks
2 mb i cs ks
zw=
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2 mw i ct cs kt ks i cs ks
2
2 mb i cs ks
zw i ct kt h=
Rrbzbh
= Transmisibilitatea (raspunsul in frecventa) drum - masa suspendata
Rrb ( )i ct kt
2 mw i ct cs kt ks
2 mb i cs ksi cs ks
i cs ks
rb ( ) arg Rrb ( ) defazajul Rrw
zwh
= Transmisibilitatea (raspunsul in frecventa) drum masa nesuspendata
Rrw ( )i ct kt
2 mw i ct cs kt ks i cs ks
2
2 mb i cs ks
rw ( ) arg Rrw ( ) defazajul
Rwbzbzw
= Transmisibilitatea (raspunsul in frecventa) masa nesuspendata - masasuspendata
Rwb ( )i cs ks
2 mb i cs ks
wb ( ) arg Rwb ( ) defazajul In lipsa amortizarii
Md2
dt2 Q K Q 0=
Obtinerea pulsatiei proprii
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1kmb
i i
1 7.038radsec
12 rad 1.12 Hz
Timpul in care e parcursa lungimea unei denivelari d 2 m v 40 kmora
t0 dv
= 2
=
2 rad vd
34.907 radsec
f 2 rad f 5.556 Hz
h ha ei t= Miscare armonicaddt
h i ha ei t= i h= Viteza miscarii armonice
d2
dt2h i ( )2 ha ei t= 2 h= Acceleratia miscarii armonice
Echilibrul de forte
F k c i( ) h z( )=
mtotd2
dt2 z c d
dth d
dtz k h z( )=
F K i C 2 M Q=Q K 2 M i C 1 F=mtot d2
dt2 z c d
dt z k z c d
dt h k h=
2 mb i c k z i c k( ) h=
Functia de transmisibilitate ( raspunsul in frecventa ) este
Trbzh
= i c kk 2 mtot i c
=AF
Fmtot g
=
Trb ( )i c k
k 2 mtot i c transmisibilitatea
c 96.154 kg s 1
Drb ( ) arg Trb ( )
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Trb 1( ) 12.533 valoarea maxima a transmisibilitatii
f 0.01 Hz 0.11 Hz 50 Hz
0 2 4 6 8 10 12 14 16 18 200
0.222
0.445
0.667
0.889
1.111
1.334
1.556
1.778
2.001
2.223
Rrb-2glRrw-2glRwb-2gl
Rrb 2 f( )Rrw 2 f( )Rwb 2 f( )
f
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0 1.4 2.8 4.2 5.6 7 8.4 9.8 11.2 12.6 140
0.3
0.6
0.9
1.2
1.5
1.8
2.1
2.4
2.7
3
Rrb-1glRrb-2glRrw-2gl
Trb 2 f( )Rrb 2 f( )Rrw 2 f( )
f
0 5 10 151
0.5
0
0.5
Rrb-2glRrw-2glRwb-2gl
rb 2 f( )
rw 2 f( )
wb 2 f( )
f
-
0.01 0.1 1 10 1000.01
0.1
1
10
100
transmisibilitateacabinascaun
Rrb 2 f( )rb 2 f( ) 0.1
Trb 2 f( )
f