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MA 105 Calculus: Lecture 2Limits and Continuity
S. Sivaji Ganesh
Mathematics DepartmentIIT Bombay
July 27, 2009
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 1 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“ if we can makethe values of f (x) arbitrarily close to L (as close to L as we like)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“ if we can makethe values of f (x) arbitrarily close to L (as close to L as we like) bytaking x to be sufficiently close to a (on either side of a)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“ if we can makethe values of f (x) arbitrarily close to L (as close to L as we like) bytaking x to be sufficiently close to a (on either side of a) but not equalto a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“ if we can makethe values of f (x) arbitrarily close to L (as close to L as we like) bytaking x to be sufficiently close to a (on either side of a) but not equalto a.
Note The value of the function at a does not play any role in the abovedefinition.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = L
and say ”the limit of f (x) as x approaches a, equals L“ if we can makethe values of f (x) arbitrarily close to L (as close to L as we like) bytaking x to be sufficiently close to a (on either side of a) but not equalto a.
Note The value of the function at a does not play any role in the abovedefinition. In fact, f need not be defined at a.See Appendix 1 for some pictures.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 2 / 27
Limits
Compute1 lim
x→1
x−1x2−1
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 3 / 27
Limits
Compute1 lim
x→1
x−1x2−1 What is the domain of this function?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 3 / 27
Limits
Compute1 lim
x→1
x−1x2−1 What is the domain of this function? What if my function
assigns 1 to 2009 ?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 3 / 27
Limits
Compute1 lim
x→1
x−1x2−1 What is the domain of this function? What if my function
assigns 1 to 2009 ? Draw Graphs.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 3 / 27
Limits
Compute1 lim
x→1
x−1x2−1 What is the domain of this function? What if my function
assigns 1 to 2009 ? Draw Graphs.2 lim
x→0
|x|x
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 3 / 27
Limits
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 4 / 27
Limits
Graph of Heaviside function H(x) =
{
0 if x < 0
1 if x ≥ 0limx→0 H(x) does
not exist. Why?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 4 / 27
Limits
Graph of Heaviside function H(x) =
{
0 if x < 0
1 if x ≥ 0limx→0 H(x) does
not exist. Why?There is no L as in the definition of limit.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 4 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike) by taking x to be sufficiently close to a and x less than a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike) by taking x to be sufficiently close to a and x less than a.
Note Once again, value of the function at a does not play any role inthe above definition.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike) by taking x to be sufficiently close to a and x less than a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike) by taking x to be sufficiently close to a and x less than a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a. Similarlydefine ”the right-hand limit of f (x) as x approaches a, equals L“
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
DefinitionLet f be a function defined on the left side (or both sides) of a, exceptpossibly at a itself. Then
limx→a−
f (x) = L
and say ”the left-hand limit of f (x) as x approaches a, equals L“ if wecan make the values of f (x) arbitrarily close to L (as close to L as welike) by taking x to be sufficiently close to a and x less than a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a. Similarlydefine ”the right-hand limit of f (x) as x approaches a, equals L“ whichis denoted by limx→a+ f (x).
limx→0−
H(x) = 0 & limx→0+
H(x) = 1
.S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 5 / 27
Limits
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 6 / 27
Limits
f (x) = sin(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 6 / 27
Limits
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 7 / 27
Limits
f (x) =
−x if x ≤ 0
x if 0 < x < 4
−x + 8 if 4 < x < 8
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 7 / 27
Limits
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 8 / 27
Limits
f (x) =
{
−x if x < 0
ex if x ≥ 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 8 / 27
Limits
f (x) =√
x
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 9 / 27
Limits
Graphs of exp(x), log(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 10 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a.
Note Once again, value of the function at a does not play any role inthe above definition.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a.Similarly define limx→a f (x) = −∞.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then
limx→a
f (x) = ∞
means that the values of f (x) can be made arbitrarily large (as large aswe like) by taking x to be sufficiently close to a (on either side of a) butnot equal to a.
Note Once again, value of the function at a does not play any role inthe above definition. In fact, f need not be defined at a.Similarly define limx→a f (x) = −∞.Go to the previous slide.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 11 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 12 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line x = a is called a vertical asymptote of the curvey = f (x) if at least one of the following statements is truelimx→a f (x) = ∞ limx→a− f (x) = ∞ limx→a+ f (x) = ∞limx→a f (x) = −∞ limx→a− f (x) = −∞ limx→a+ f (x) = −∞ .
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 12 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line x = a is called a vertical asymptote of the curvey = f (x) if at least one of the following statements is truelimx→a f (x) = ∞ limx→a− f (x) = ∞ limx→a+ f (x) = ∞limx→a f (x) = −∞ limx→a− f (x) = −∞ limx→a+ f (x) = −∞ .
Note Give some examples by drawing their graphs.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 12 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line x = a is called a vertical asymptote of the curvey = f (x) if at least one of the following statements is truelimx→a f (x) = ∞ limx→a− f (x) = ∞ limx→a+ f (x) = ∞limx→a f (x) = −∞ limx→a− f (x) = −∞ limx→a+ f (x) = −∞ .
Note Give some examples by drawing their graphs.Go back and check if we already some examples.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 12 / 27
Limits
f (x) = tan(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 13 / 27
Limits
f (x) = tan(x)
Question List all the vertical asymptotes.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 13 / 27
Limits
f (x) =1x2 , for x 6= 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 14 / 27
Limits
f (x) =1x
, for x 6= 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 15 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if eitherlimx→∞ f (x) = b
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if eitherlimx→∞ f (x) = b or
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if eitherlimx→∞ f (x) = b or limx→−∞ f (x) = b holds.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if eitherlimx→∞ f (x) = b or limx→−∞ f (x) = b holds.
Note Give some examples by drawing their graphs.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
DefinitionLet f be a function defined on both sides of a, except possibly at aitself. Then The line y = b is called a horizontal asymptote of the curvey = f (x) if eitherlimx→∞ f (x) = b or limx→−∞ f (x) = b holds.
Note Give some examples by drawing their graphs.Go back and check if we already some examples.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 16 / 27
Limits
f (x) = sin(1x
), for x > 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 17 / 27
Limits
f (x) = sin(1x
), for x > 0
Question Can you explain why limx→0+ f (x) does not exist?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 17 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
4 limx→a
1g(x) = 1
limx→a
g(x)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
4 limx→a
1g(x) = 1
limx→a
g(x) provided · · ·
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
4 limx→a
1g(x) = 1
limx→a
g(x) provided · · ·
Polynomials,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
4 limx→a
1g(x) = 1
limx→a
g(x) provided · · ·
Polynomials,Rational functions,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limit laws
We have seen some limit laws in the context of sequences. Similarlimit laws also hold for limits of functions.Let f , g be two functionsdefined on both sides of a, except possibly at a itself.Assume thatlimx→a
f (x) and limx→a
g(x) exist. Then
1 limx→a
(f (x) + g(x)) = limx→a
f (x) + limx→a
g(x)
2 limx→a
cf (x) = c limx→a
f (x) for any number c.
3 limx→a
f (x)g(x) = limx→a
f (x) limx→a
g(x)
4 limx→a
1g(x) = 1
limx→a
g(x) provided · · ·
Polynomials,Rational functions, all trigonometric functions whereverthey are defined, have property called direct substitution property:
limx→a
f (x) = f (a)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 18 / 27
Limits
f (x) = x sin(1x
), for x 6= 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 19 / 27
Limits
f (x) = x sin(1x
), for x 6= 0
What is limx→0
x sin(1x )?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 19 / 27
Limits
f (x) = x sin(1x
), for x 6= 0
What is limx→0
x sin(1x )? Why?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 19 / 27
Limits
f (x) = x sin(1x
), for x 6= 0
What is limx→0
x sin(1x )? Why? How to prove?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 19 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
The Squeeze Theorem
If f (x) ≤ g(x) ≤ h(x) when x is near a (except possibly at a) and
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
The Squeeze Theorem
If f (x) ≤ g(x) ≤ h(x) when x is near a (except possibly at a) and
limx→a
f (x) = limx→a
h(x) = L,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
The Squeeze Theorem
If f (x) ≤ g(x) ≤ h(x) when x is near a (except possibly at a) and
limx→a
f (x) = limx→a
h(x) = L,
thenlimx→a
g(x) = L.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
The Squeeze Theorem
If f (x) ≤ g(x) ≤ h(x) when x is near a (except possibly at a) and
limx→a
f (x) = limx→a
h(x) = L,
thenlimx→a
g(x) = L.
Note that −x ≤ x sin(1/x) ≤ x
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Squeeze (Sandwich) Theorem for Limits
TheoremIf f (x) ≤ g(x) when x is near a (except possibly at a) and the limits of fand g both exist as x approaches a, then
limx→a
f (x) ≤ limx→a
g(x).
The Squeeze Theorem
If f (x) ≤ g(x) ≤ h(x) when x is near a (except possibly at a) and
limx→a
f (x) = limx→a
h(x) = L,
thenlimx→a
g(x) = L.
Note that −x ≤ x sin(1/x) ≤ x and apply Squeeze theorem.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 20 / 27
Limits
behaviour of sin(x) at infinity
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 21 / 27
Limits
behaviour of sin(x) at infinity
Question Can you explain why limx→∞ sin(x) does not exist?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 21 / 27
Limits
behaviour of sin(x) at infinity
Question Can you explain why limx→∞ sin(x) does not exist? Did wesee this already?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 21 / 27
Limits
behaviour of sin(x) at infinity
Question Can you explain why limx→∞ sin(x) does not exist? Did wesee this already? Recall sin(n) exercise; solve it graphically.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 21 / 27
ǫ-δ definition of Limit
Let f be a function defined on some
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
if for every ǫ > 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
if for every ǫ > 0 there is a number δ > 0 such that
|f (x) − L| < ǫ whenever 0 < |x − a| < δ.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
if for every ǫ > 0 there is a number δ > 0 such that
|f (x) − L| < ǫ whenever 0 < |x − a| < δ.
Define the precise definitions of left-hand and right-hand limits.Play the ǫ-δ game in many examples,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of Limit
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we say that the limit of f (x) as xapproaches a is L and we write
limx→a
f (x) = L.
if for every ǫ > 0 there is a number δ > 0 such that
|f (x) − L| < ǫ whenever 0 < |x − a| < δ.
Define the precise definitions of left-hand and right-hand limits.Play the ǫ-δ game in many examples, including the next one.Also, see Appendix 2.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 22 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if for every M > 0
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if for every M > 0 there is a number δ > 0 such that
f (x) > M whenever 0 < |x − a| < δ.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if for every M > 0 there is a number δ > 0 such that
f (x) > M whenever 0 < |x − a| < δ.
Define limx→a f (x) = −∞
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if for every M > 0 there is a number δ > 0 such that
f (x) > M whenever 0 < |x − a| < δ.
Define limx→a f (x) = −∞Prove that limx→0
1x2 = ∞.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
ǫ-δ definition of infinite imits
Let f be a function defined on some open interval that contains a,except possibly at a itself. Then we write
limx→a
f (x) = ∞
if for every M > 0 there is a number δ > 0 such that
f (x) > M whenever 0 < |x − a| < δ.
Define limx→a f (x) = −∞Prove that limx→0
1x2 = ∞. What do we need to do?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 23 / 27
Continuity
1 A function f is continuous from the right at a if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
4 A function f is continuous on an interval if
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
4 A function f is continuous on an interval if f is continuous at everynumber in the interval.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
4 A function f is continuous on an interval if f is continuous at everynumber in the interval.In case f is defined only on one side of anend point of the interval,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
4 A function f is continuous on an interval if f is continuous at everynumber in the interval.In case f is defined only on one side of anend point of the interval, continuous at the end point means
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
1 A function f is continuous from the right at a if
limx→a+
f (x) = f (a).
2 A function f is continuous from the left at a if
limx→a−
f (x) = f (a).
3 A function f is continuous at a if
limx→a
f (x) = f (a)
4 A function f is continuous on an interval if f is continuous at everynumber in the interval.In case f is defined only on one side of anend point of the interval, continuous at the end point meanscontinuous from the right or continuous from the left.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 24 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant),
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....),
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
Thus, Polynomials,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
Thus, Polynomials, Rational functions,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
Thus, Polynomials, Rational functions, trigonometric functions
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
Thus, Polynomials, Rational functions, trigonometric functions are allcontinuous
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Continuity
Note that the definition for continuity of a function f at a is equivalent tothe following:
1 The function f must be defined at a. i.e., a is in the domain of f ,2 limx→a f (x) exists, and3 limx→a f (x) = L.
TheoremIf f and g are continuous at a, then the functions f + g, f − g, cg (c is aconstant), fg, f/g (provided ....), f◦g (composition of f and g, wheneverit makes sense) are all continuous.
Thus, Polynomials, Rational functions, trigonometric functions are allcontinuous on their respective domains.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 25 / 27
Properties of continuous functions
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?Roughly speaking,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?Roughly speaking, a continuous function is
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?Roughly speaking, a continuous function is the one whose graphcan be drawn without
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?Roughly speaking, a continuous function is the one whose graphcan be drawn without lifting pen from the paper.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
Properties of continuous functions
Take a continuous function on an interval. Take any two values in therange and take any third value lying between them. What can we sayabout it? Does it also belong to the range?
Intermediate value theoremSuppose that f is continuous on the closed interval [a, b] and let N beany number between f (a) and f (b), where f (a) 6= f (b). Then thereexists a c ∈ (a, b) such that f (c) = N.
Understand what is meant by between.Verify the validity of the theorem by drawing graphs ofmanycontinuous functions.Intersting question Is every continuous function given by aformula?Roughly speaking, a continuous function is the one whose graphcan be drawn without lifting pen from the paper.Can we draw the graph of every continuous function?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 26 / 27
about Intermediate Value Theorem
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue?
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
For odd degree polynomials P(x) with real coefficients,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
For odd degree polynomials P(x) with real coefficients, if we canshow that P takes positve as well as negative values,
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
For odd degree polynomials P(x) with real coefficients, if we canshow that P takes positve as well as negative values, we concludethat the polynomial P(x) has a real root.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
For odd degree polynomials P(x) with real coefficients, if we canshow that P takes positve as well as negative values, we concludethat the polynomial P(x) has a real root. Prove
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27
about Intermediate Value Theorem
Proof is non-trivial and uses V.I.P. of Real numbers.
Formulate a converse of Intermediate value theorem and is ittrue? Draw graphs and find out for yourself.
Applications of Intermediate Value Theorem
Helps us in deciding a given function is not continuous on aninterval.
For odd degree polynomials P(x) with real coefficients, if we canshow that P takes positve as well as negative values, we concludethat the polynomial P(x) has a real root. Prove
See Appendix 3 also.
S. Sivaji Ganesh (IIT Bombay) MA 105 Calculus: Lecture 2 July 27, 2009 27 / 27