Phuong Trinh Mu Logarit
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Transcript of Phuong Trinh Mu Logarit
PHNG TRNH M
PHNG TRNH MBi 1. Gii cc phng trnh sau
a.
b.
c. (x 3x + 3)2x 1 = 0d.
e.
f. 52x+1 + 7x+1 175x 35 = 0
g.
h. 4.3x + 15x 5x+1 = 20
Bi 2. Gii cc phng trnh saua. 5x. = 3
b. 5x+1.22x1 = 50c.
d.
e.
g.
h.
Bi 3. Gii cc phng trnh saua.
b.
c. 34x+8 4.32x+5 + 27 = 0
d.
e.
f. 5.23|x1| 3.253x + 7 = 0
g.
h. 25lg x 4.xlg 5 5 = 0
i.
Bi 4. Gii cc phng trnh sau
a. 25x 2(3 x)5x + 2x 7 = 0
b. 3.25x2 + (3x 10)5x2 + 3 x = 0
c.
d. (x + 4)9x (x + 5)3x + 1 = 0
e.
f. 9x (x + 2)3x 2(x + 4) = 0
g. x (3 2x)x + 2(1 2x) = 0
Bi 5. Gii cc phng trnh sau
a. 27x + 12x = 2.8xb. 3.16x + 2.81x = 5.36xc. 25x + 10x = 22x+1d.
e. 25x 12.2x 6,25.0,16x = 0f. 3.8x + 4.12x 18x 2.27x = 0Bi 6. Gii cc phng trnh sau
a.
b.
c.
d.
e.
f.
g. = 0Bi 7. on nghim v chng minh nghim hu hna. 3x + 4x = 5x
b. 2x+1 = 4x + x 1c. 4x + 7x = 9x + 2
d. 2x = 3x/2 + 1
e. (1/2)x = x 1/2f.
g. 5x + 4x + 3x + 2x = 2x + 3x + 6x 2x + 5x 7x + 17
h. 9.7x + 1 = 26/xi. 3x + 5x = 6x + 2j. 4x + 9x = 25x.
k. = (2x + x + 1)2x.
. = x + 8x 16 m.
n. = (2 + x)1+|x|.
o. 8 x.2x + 23x x = 0
p. (x 7x + 12)3x = x + 8x 19x + 12
q.
r.
s.
t.
PHNG TRNH LOGARITBi 1. Gii cc phng trnh sau
a. log9 (x + 8) = log3 (x + 26) 2b. log4 x + log4 (10 x) 2 = 0
c.
d. log5 (x 1) log1/5 (x + 2) = 0
e. log3 (x 6) = log3 (x 2) + 1f. lg (x 2) + log (x 3) + lg 5 1 = 0
g. lg (3x 24x) = lg 200 x lg 2h.
i. 2log3 (x 2) + log3 (x 4) = 0j.
Bi 2. Gii cc phng trnh sau
a.
b. 1 + lg (x 2x + 1) lg (x + 1) = 2 lg (1 x)c. log2 log4 x = log4 log2 x
d.
e. log2 log3 x = log3 log2 x
f. log2 log3 x + log3 log2 x = log3 log3 x
g. log2 (x x + 1) + log2 (x + x + 1) = log2 (x4 x + 1) + log2 (x4 + x + 1)
h. log2 x + log7 x 2 log2 x log7 x = 0i. lg (x x + 10) = lg 2 [log2 (x + 2) + log2 3]Bi 3. Gii cc phng trnh sau
a. log2 (9 2x) 3 + x = 0
b. log3 (4.3x1 1) = 2x 1
c.
d. log4 (3.2x+1 5) x = 0
e. log2 (2x 1) log4 (2x+1 2) = 1f. = 0
g. log2 (4x + 1) = x + log2 (2x+3 6)h. 2lg 2 + (1 + )lg 3 = lg (3x + 27)Bi 4. Gii cc phng trnh sau
a. = 0
b. logx+1 (2x + 2x 3x + 1) = 3
c. logx3 (x 1) = 2
d. logx (x 2) = 1
e. log3x+5 (9x + 8x + 2) 2 = 0f. log5 (5x) = 1Bi 5. Gii cc phng trnh sau (t n ph)
a.
b.
c. 6(logx 2 log4 x) = 7
d. = 0
e.
f.
g.
h. log2x x + 40log4x = 14 log16x xi. log2 log4 x + log4 log2 x 2 = 0j.
k. log2x1 (2x + x 1) + logx+1 (2x 1) 4 = 0Bi 6. Gii cc phng trnh sau (t n ph)
a. + (x 12)log3 x + 11 x = 0b.
c. x 2(x + 1)log2 x = 4
d. + (x 1)log2 x + 2x 6 = 0e. (x + 2) + 4(x + 1) log3 (x + 1) 16 = 0f.
g. + (x 5)log3 (x + 1) 2x + 6 = 0
h. = 0
i. log2 (x + 3x + 1) + log2 (x + 7x + 12) = 3 + log2 3Bi 7. Gii cc phng trnh sau (t n ph)
a.
b. log2 (x 3) + log3 (x 2) = 2
c. log3 (x + 1) + log5 (2x + 1) = 2d.
e.
f.
g.
h. log3x+7 (9 + 12x + 4x) + log2x+3 (6x + 23x + 21) = 4
i.
j. log2 (3x 4) log2 x =
k. = 1.
Bi 8. on nghim v chng minh nghim hu hn.a.
b.
c. log5 (x + 3) 3 + x = 0
d. 4(x 2)[log2 (x 3) + log3 (x 2)] = 15(x + 1)e. log2 (x x 6) + x = log2 (x + 2) + 4f.
g. log3 (x + 2x + 1) = log2 (x + 2x)h. x + log (x x 6) = 4 + log (x + 2)i. 2x x + log5 x log5 (x + x + 4) = 0j. 3x 2x = log2 (x + 1) log2 x
k. log2 (x x + 1) log2 (2x 4x + 3) = x 3x + 2PHNG TRNH M LOGARIT TRONG THI CAO NG, I HC
Cu AUTONUM (D 03) Gii phng trnh:
S: 1; 2.
Cu AUTONUM (A 03) Gii h phng trnh
S: (log2 3 1; log2 3 1)Cu AUTONUM (A 04) Gii h phng trnh
S: (3; 4).Cu AUTONUM (DB B 04) Gii bt phng trnh:
S: S = (; 2) U (4; +)Cu AUTONUM (DB D 04) Gii h phng trnh:
S: (1; 1), (1; 0)
Cu AUTONUM (B 05) Gii h phng trnh
S: (1; 1), (2; 2)
Cu AUTONUM (A 06) Gii phng trnh: 3.8x + 4.12x 18x 2.27x = 0
S: x = 1.
Cu AUTONUM (B 06) Gii bt phng trnh: log5 (4x + 144) 4log5 2 < 1 + log5 (2x2 + 1)S: (2; 4)
Cu AUTONUM (D 06) Gii phng trnh
S: 1; 0.
Cu AUTONUM (A 07) Gii bt phng trnh: 2log3 (4x 3) log1/3 (2x + 3) 2.S: [3/4; 3]Cu AUTONUM (B 07) Gii phng trnh:
S: 1; 1.
Cu AUTONUM (D 07) Gii phng trnh:
S: log2 3
Cu AUTONUM (A 08) Gii phng trnh: log2x1 (2x + x 1) + logx+1 (2x 1) = 4S: 2; 5/4.
Cu AUTONUM (B 08) Gii bt phng trnh:
S: (4; 3) U (8; +)
Cu AUTONUM (D 09) Gii bt phng trnh: 0S:
Cu AUTONUM (C 08) Gii phng trnh:
S: 1; 3.
Cu AUTONUM (A 09) Gii h phng trnh:
S: (2; 2), (2; 2)
Cu AUTONUM (B 10) Gii h phng trnh:
S: (1; 1/2)
Cu AUTONUM (D 10) Gii h phng trnh:
S: (0; 2), (3; 1)
Cu AUTONUM (D 10) Gii phng trnh:
S: 1; 2.
Cu AUTONUM (D 11) Gii phng trnh:
S: x = 0
Cu AUTONUM (C 12) Gii bt phng trnh: log2 (2x).log3 (3x) > 1S: x > 1Cu AUTONUM (B 13) Gii h phng trnh:
S: (3; 1)
Cu AUTONUM (D 13) Gii phng trnh:
S:
Cu AUTONUM (D 14) Gii phng trnh: log2 (x 1) 2log4 (3x 2) + 2 = 0S: x = 2
Cu AUTONUM (C 14) Gii phng trnh: 32x+1 4.3x + 1 = 0S: x = 0 hoc x = 1.
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