Post on 05-Feb-2016
description
Buiten haakjes halen
2a+4b= 2(a+2b)
3a+6= 3(a+2)3a+3.2=
4a+6= 2.2a+2.3= 2(2a+3)
2a+2= 2a+2.1= 2(a+1)
a2+2ab= a.a+2ab= a(a+2b)
2b2+4ab = 2.b.b+2.2.a.b= 2b(b+2.a)
6ab2+9a2b= 3.2.a.b.b+3.3.a.a.b= 3ab(2b+3a)
3ab2+12a2b-4a3=
4xy2+6x2y-2xy=