SCHOOL BASED ASSESSMENT 2020 GRADE 5 Model Paper ...pec.punjab.gov.pk/system/files/G5 Math -...

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[Grade-5, Mathematics Part-B] Page 1 of 4 SCHOOL BASED ASSESSMENT 2020 GRADE 5 MATHEMATICS PART B (Subjective Type) Rubric for Model Paper Note: If students use any correct method other than given in the rubrics that too, they will be awarded full marks. ٹ : ا ل ا اور در ۔ د رے Q.No.26 (a) Solve. 21367 × 219 ۔21367 × 219 192303 213670 4273400 4679373 1 mark 0.5 mark 0.5 mark 1 mark (3 ) (b) Solve. 30+ (81 ÷ 9) × 7 10 ۔ 30+ (81 ÷ 9) × 7 10 =30+ 9 × 7 − 10 1mark =30+ 63 − 10 0.5mark =93 −10 0.5 mark =83 1mark (3 ) (c)Verify that 20 × (40 30) = ( 20 × 40) ( 20 × 30) ل ۔L.H.S= 20 × (40 30) = 20×10 1mark = 200__________ (a) 0.5mark R.H.S= ( 20 × 40) ( 20 × 30) = 800 600 1 mark = 200___________ (b) 0.5mark From (a) and (b) L.H.S = R.H.S 1mark (4 ) Model Paper

Transcript of SCHOOL BASED ASSESSMENT 2020 GRADE 5 Model Paper ...pec.punjab.gov.pk/system/files/G5 Math -...

Page 1: SCHOOL BASED ASSESSMENT 2020 GRADE 5 Model Paper ...pec.punjab.gov.pk/system/files/G5 Math - Rubrics.pdf · [Grade-5, Mathematics Part-B] Page 1 of 4 ... Find HCF of 25, 45 and 50

[Grade-5, Mathematics Part-B] Page 1 of 4

SCHOOL BASED ASSESSMENT 2020

GRADE 5

MATHEMATICS PART – B (Subjective Type)

Rubric for Model Paper Note: If students use any correct method other than given in the rubrics that too, they will be awarded full marks.

وت یھب وپرے ربمن دےی اجںیئ ےگ۔ ںی اور درتس رطہقی اامعتسل رکےت یئارگ ہبلط وک: ونٹ

Q.No.26 (a) Solve. 21367 × 219 ۔لح رکںی

21367

× 219

192303

213670

4273400

4679373

1 mark

0.5 mark

0.5 mark

1 mark

(3 )

(b) Solve. 30+ (81 ÷ 9) × 7 − 10 لح رکںی۔

30+ (81 ÷ 9) × 7 − 10

=30+ 9 × 7 − 10 1mark

=30+ 63 − 10 0.5mark

=93 −10 0.5 mark

=83 1mark

(3 )

(c)Verify that 20 × (40 −30) = ( 20 × 40) − ( 20 × 30) ۔رکںی ڑپاتل

L.H.S= 20 × (40 −30)

= 20×10 1mark

= 200__________ (a) 0.5mark

R.H.S= ( 20 × 40) − ( 20 × 30)

= 800 – 600 1 mark

= 200___________ (b) 0.5mark

From (a) and (b)

L.H.S = R.H.S 1mark

(4 )

Model Paper

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[Grade-5, Mathematics Part-B] Page 2 of 4

Q.No. 27 (a) Find the smallest number which is exactly divisible by12, 24, 72 and 90.

۔ میسقت وہ اوپر اوپررپ 09 اور 21 ،12 ،21وجرکںی ولعممدعد ےس وھچاٹ وھچ ےٹ وہ

Smallest number 1 5×3×3×2×2×2 =وھچےٹ ےس وھچاٹ دعد mark

Smallest number 1 360 = وھچےٹ ےس وھچاٹ دعد mark

(5 )

(b) Find HCF of 25, 45 and 50 by prime factorization method.

-زجتی ولعمم رکںی رفم داک اعدامظع ذبرہعی 29 اور 22، 12

Prime factorization of 25 = 5×5 1 mark

رفمد زجتی

Prime factorization of 45 = 3×3×5 1 mark

رفمد زجتی

Prime factorization of 50 = 2×5×5 1 mark

رفمد زجتی

Common factor = 5 1 mark

رضیب و زجرتشمک

H.C.F 1 5 =اعدامظع mark

(5)

Q.No.28 (a) Price of a bicycle is Rs.5000. The shopkeeper sold it at 10% discount. What did

customer pay to the shopkeeper?

%10 رمق ادا یک؟ راعتی رپ رفوتخ ایک۔ اگکہ ےن داکدنار وک ینتک روےپ ےہ۔ داکدنار ےن اےس 2999یک تمیق ئالکیاکی

Price of a bicycle is= Rs.5000

یک تمیق ئالکی

10% discount = 5000 ×10

100 2 marks

10% راعتی

= 500 1 mark

( 5 )

12, 24, 72, 90

6 , 12, 36, 45

3 , 6, 18, 45

2

2

3, 3, 9 45

2

3

1, 1, 3, 15 3

0.5 Mark

0.5 Mark

0.5 Mark

0.5 Mark

1, 1, 1, 5 5 0.5 Mark

1, 1, 1, 1 0.5 Mark

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[Grade-5, Mathematics Part-B] Page 3 of 4

customer pays to the shopkeeper= 5000 -500 1 mark

وج رمق ادا یکاگکہ ےن داکدنار وک

=Rs. 4500 1 mark

(b) A door costs Rs.8000 to a carpenter. He sells it for Rs. 10000. Find his percentage profit.

اکی

ئ

۔ولعمم رکںی روےپ ںیم رفوتخ رکات ےہ۔ اُس اک عفن دصیف29999روےپ رخچ آات ےہ۔ وہ اےس 0999انبےن رپ دروازہ اک ڑب ھ

Cost of door رپ التگدروازہ = Rs. 8000

Sale price رفوتخ یک تمیقدروازہ = Rs. 10000

Profit عفن = 10000 -8000 = 2000 1 mark ربمن

Percentage profit دصیف عفن = 2000

1008000

2 marks ربمن

= 25 1 mark ربمن

= 25% 1 mark ربمن

(5)

Q.No.29 (a) The length of a square shaped room is 5 metres. Find the cost of flooring it at the

rate of Rs.600 per square metre.

روےپ یف رمعب رٹیم ےہ۔ رفش اگلےن اک رخچ ولعمم رکںی۔ 699رفش اگلےن اک رخچ ںیماس رٹیم ےہ۔ 2رمعب لکش ےک اکی رمکے یک ابملیئ

Length of room = 5 m

رمک ے یک ابملیئ

Area of square = Side × Side

Area of room = 5 × 5 1 mark

رمکے اک رہبق

= 25m

2

1 mark

Cost of flooring per metre square = Rs. 600

یف رمعب رٹیمرفش اگلےن اک رخچ

Cost of flooring 25 metre square = 25 × 600 2 mark

رمعب رٹیم رفش اگلےن اک رخچ 12

= Rs. 15000 1 mark

(5)

(b) Construct a rectangle with length 5 cm and width 3 cm.

یٹنیس رٹیم وہ۔ 3یٹنیس رٹیم اور وچڑایئ 2سج یک ابملیئ ںیئلیطتسم انب اکی

For drawing line segment of given length 1 – Mark

Making angle of 90o at each end points 2 – Marks

For drawing two arcs 1- Mark

For construction of correct rectangle 1- Mark

ےنچنیھک رپ ہعطق طخ اک ابملیئ درتس ربمن 2

90 اک زاوہی انبےن رپ

o

ربمن 1 ہعطق طخ ےک رہ رسے رپ

(5)

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[Grade-5, Mathematics Part-B] Page 4 of 4

ربمن 2 دو وقںیس ےنچنیھک رپ

م

ل درتس ی

ظ

ست

یک لیمکت رپ ربمن 2

Q.No.30 (a) Nasir’s obtained marks out of 50 each time in five different English tests are

shown in the following table. Find the average marks he obtained in each test.

ںیم ےسوج ربمن احلص ےیک وہ ےچین دےی ےئگ ںی۔ اس ےک رہ ٹسیٹ ںیم اوطس احلص رکدہ ربمن ولعمم رکںی۔ 29 ہعف درہ انرص ےن ارگنزیی ےک اپچن فلتخم وٹسیٹں ںیم

English Test ٹسیٹارگنزیی اک First الہپ Second دورسا Third رسیتا Fourth وچاھت Fifth اپوچناں

Obtained Marks ربمناحلص رکدہ 40 35 45 30 25

Total Marks ربمن لک = 40+35+45+30+25= 175 2 marks

Average Marks ربمناوطس = 175

5 2 marks

= 35 1mark

(4)

(b) The following table shows the number of students in five different classes of a school.

Draw a column graph representing the given information.

ں وموجد ہبلط یک دعتاد ںاکی وکسل یک اپچن فلتخم امج وتع مت

- رکںیرہ اظ ےک ذرےعی ولعمامت وک اکمل رگاف دی یئگ -اظرہ ایک ایگ ےہ وک ےچین دےی ےئگ لبیٹ ںیم

Class امج تع One اول Two دومئ Three وسمئ Four اہچرم Five مجنپ

Number of students

ہبلط یک دعتاد20 25 30 35 40

For each correct bar 1 mark [1 ×5 = 5 marks]

درتس ابر ےک ےیلرہ

(6)