Papula.integreren.substitutie Tabel
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INTEGRATIE MET SUBSTITUTIE type integraal substitutie oplossing voorbeelden A. dx b x a f u = a x + b a dx du a du dx 1. dx 3 x 2 3 2. dx 5 x 4 3. dx e 2 x 3 1. u = 2 x – 3 2. u = 4 x + 5 3. u = 3 x + 2 B. dx x ' f . x f u = f (x) x ' f dx du f'(x).dx = du ½ f 2 (x) + C 1. dx x cos . x sin 2. dx x x ln 1. u = sin x 2. u = ln x C. dx x f x ' f u = f (x) x ' f dx du f'(x).dx = du ln |f (x)| + C 1. dx 1 x 3 x 3 x 2 2 2. dx 5 e e x x 3. dx x cos x sin 1. u = x 2 – 3 x + 1 2. u = e x + 5 3. u = cos x D. dx x a , x f 2 2 x = a.Sin u u cos . a du dx dx = a.cos u.du let op : √(a 2 – x 2) =a.cosu 1. dx x r 2 2 2. dx x r . x 2 2 3. 2 x 4 dx 1. x = r.sin u 2. x = r.sin u 3. x = 2.sin u
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Papula.integreren.substitutie Tabel
Transcript of Papula.integreren.substitutie Tabel
INTEGRATIE MET SUBSTITUTIE type integraal substitutie oplossing voorbeelden
A. dxbxaf u = a x + b
adxdu
adu
dx
1. dx3x2 3
2. dx5x4
3. dxe 2x3
1. u = 2 x – 3 2. u = 4 x + 5 3. u = 3 x + 2
B. dxx'f.xf u = f (x)
x'fdxdu
f'(x).dx = du
½ f2 (x) + C 1. dxxcos.xsin
2. dxxxln
1. u = sin x 2. u = ln x
C. dxxfx'f
u = f (x)
x'fdxdu
f'(x).dx = du
ln |f (x)| + C 1.
dx1x3x
3x22
2. dx
5ee
x
x
3. dxxcosxsin
1. u = x2 – 3 x + 1 2. u = ex + 5 3. u = cos x
D. dxxa,xf 22 x = a.Sin u
ucos.adudx
dx = a.cos u.du let op : √(a2 – x2) =a.cosu
1. dxxr 22
2. dxxr.x 22
3. 2x4
dx
1. x = r.sin u 2. x = r.sin u 3. x = 2.sin u