Ma Tran Kiem Tra Ly 11 Tron Bo
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kim tra 1 titHc k I lp 11 theo chng trnh chun
A. Bng trng sI- trc nghim
Ch
S tit L thuytS tit thc Trng s
LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 20 21
Chng 2: Dng in khng i 14 8 5,6 8,4 24 35
Tng 24 15 10,5 13,5 44 56
II- T lun
Ch S tit L thuytS tit thc Trng s
LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 20 21
Chng 2: Dng in khng i 14 8 5,6 8,4 24 35
Tng 24 15 10,5 13,5 44 56
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B. Tnh im
.I- trc nghim khch quan
( 30 cu)Thi gian lm bi 45 phtBng tnh im, tnh s cu
Ch stit
Lthuyt
s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 20 21 6 6 2 2Chng 2: Dng in khng i 14 8 5,6 8,4 24 35 7 11 2.4 3.6Tng 24 15 10,5 13,5 44 56 13 17 4.4 5.6
II- T lun( 5 cu)Thi gian lm bi 45 phtBng tnh im, tnh s cu
Ch stit
Lthuyt
s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 20 21 1 1 2 2Chng 2: Dng in khng i 14 8 5,6 8,4 24 35 1 2 2 4Tng 24 15 10,5 13,5 44 56 2 3 4 6
C. Thit k ma trn1. Ma trn cho t lun
Tn ch Nhn bit(cp 1)
Thng hiu(Cp 2)
Vn dng CngCp 3 Cp 4
Chng 1: in tch in trng (10 tit)1.in tch
nh lutNu c cc cchnhim in mt vt (c
Pht biu cnh lut Cu-lng
Vn dng c nhlut Cu-lng gii
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Culng(1 tit = 4,2%)
xt, tip xc v hngng).
v ch ra c imca lc in giahai in tch im.
c cc bi tp ivi hai in tchim.
2. Thuyt
electrn(1 tit = 4,2%)
Nu c cc ni dung
chnh ca thuytlectron.Pht biu c nh lut
bo ton in tch.
Vn dng c
thuyt lectron gii thch cc hintng nhim in
3. in trng(2 tit)= 8,3%
Nu c in trngtn ti u, c tnhcht g.Pht biu c nhngha cng intrng.
4. Cng calc in
(1 tit)= 4,2%
Nu c trng tnhin l trng th.
5. in th(1 tit)= 4,2%
Pht biu c nhngha hiu in th giahai im ca in trngv nu c n v ohiu in th.
Nu c miquan h giacng intrng u v hiuin th gia haiim ca intrng . Nhn
Gii c bi tp vchuyn ng ca mtin tch dc theong sc ca mtin trng u.
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bit c n vo cng intrng.
6. T in(1 tit)= 4,2%
Nu c nguyn tccu to ca t in.
Nhn dng c cc tin thng dng.
Pht biu nhngha in dungca t in vnhn bit cn v o indung.
Nu c nghacc s ghi trnmi t in.
Nu c in
trng trong tin v mi intrng u mangnng lng.
S cu (im)T l %
1(2 im)20%
1(2 im)20%
2(4 im)40%
Chng II. DNG IN KHNG I (11tit)
1.Dng inkhng i
(2 tit)= 8,3%
Nu c dng inkhng i l g.
Nu c sut in ngca ngun in l g.
Nu c cu tochung ca ccngun in hohc (pin, acquy).
2. in nng Vit c cng
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(2 tit)= 8,3% thc tnh cngca ngun in :Ang = Eq = EItVit c cngthc tnh cng
sut ca ngunin : Png = EI
Vn dng c cngthc Ang = EIttrong cc bi tp.Vn dng c cng
thc Png = EItrong cc bi tp.
3. nh lutm i viton mch
(1tit)= 4,2%
Pht biu c nh lutm i vi ton mch.
Tnh c hiu sutca ngun inVn dng c h
thcE
N
IR r
=+
hoc
U = E Ir gii ccbi tp i vi tonmch, trong mchngoi gm nhiu nhtl ba in tr.
4. on mchcha ngun
in(1 tit = 4,2%)
Vit c cngthc tnh sut in
ng v in trtrong ca bngun mc (ghp)ni tip, mc(ghp) song song.
Nhn bit ctrn s v trongthc t, b ngun
Tnh c sut inng v in trtrong ca cc loi bngun mc ni tiphoc mc song song.
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mc ni tip hocmc song song.
5. Phngphp gii biton v mch
in(1 tit = 4,2%)
Vn dng linh hot cccng thc gii cc
bi ton v mch in
6. Thc hnh(2 tit = 8,3%)
Nhn bit c,trn s v trongthc t, b ngunmc ni tip hocmc song song
n gin.S cu
(im)T l %
1(2 im)20%
2(4im)40%
3(6im)60%
Tng s cu(im)T l %
2(4 im)40%
3(6im)60%
5(10 im)100%
Ma trn cho trc nghimKHUNG MA TRN KIM TRA
(Bng m t cc tiu ch ca kim tra)Mn: Vt l lp 11 THPT, chng trnh Chun
(Thi gian: 45 pht, 30 cu trc nghim)Phm vi kim tra: Chng 1. in tch in trng; Chng 2. Dng in khng i..
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Tn Ch Nhn bit
(Cp 1)
Thng hiu
(Cp 2)
Vn dng
CngCp thp
(Cp 3)
Cp cao
(Cp 4)
Chng 1. in tch in trng
1 in tch nh lut Cu-
lng
Nu c cccch nhimin mt vt(c xt, tip
xc v hngng).
Pht biu c nh lutCu-lng v ch ra c imca lc in gia hai intch im.
Vn dng c nh lutCu-lng gii c cc
bi tp i vi hai intch im.
5 cu5/3
1 cu 1 cu 3 cu
2. Thuyt
electrn
Nu c ccni dung chnh
ca thuytlectron.Pht biu cnh lut boton in tch.
Vn dng c thuytlectron gii thch cc
hin tng nhim in
2 cu2/3
2 cu
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3. in trngNu c intrng tn ti u, c tnhcht g.
Pht biu cnh nghacng intrng.
1 cu1/3
1cu
4. Cng calc in
Nu ctrng tnh
in l trngth. 1 cu
1/3
1cu
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5. in thPht biu cnh nghahiu in thgia hai imca in
trng v nuc n v ohiu in th.
Nu c mi quan h giacng in trng uv hiu in th gia haiim ca in trng .
Nhn bit c n v ocng in trng.
Gii c bi tp vchuyn ng ca mtin tch dc theo ngsc ca mt in trng
u.
2 cu2/3
1cu 1cu
6. T in Nu cnguyn tc cuto ca t in.
Nhn dng
c cc tin thngdng.
Pht biu nh ngha indung ca t in v nhn
bit c n v o indung.
Nu c ngha cc s ghi
trn mi t in.Nu c in trng trongt in v mi in trngu mang nng lng.
1 cu1/3
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1 cu
Chng 1.S cu 12
S im 4T l 40%
S cu 6S im 2
S cu: 6S im: 2
S cu 12 .4,0im=40%
Chng 2. Dng in khng i
1.Dng in
khng i
Nu c
dng inkhng i lg.
Nu c sutin ng cangun in lg.
Nu c cu to chung ca
cc ngun in ho hc(pin, acquy).
2 cu2/3
2 cu
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2. in nng Vit c cng thc tnhcng ca ngun in : Ang= Eq = EItVit c cng thc tnhcng sut ca ngun in :
Png = EI
Vn dng c cngthc Ang = EIttrong cc bi tp.Vn dng c cngthc Png = EItrong cc bi tp.
5 cu5/3
2 cu3 cu
3. nh lutm i viton mch
Pht biu cnh lut mi vi tonmch.
Tnh c hiu sut cangun inVn dng c h thc
E
N
IR r
=+
hoc U = E
Ir gii cc bi tp ivi ton mch, trong mch ngoi gm nhiunht l ba in tr.
5 cu5/3
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1 cu 4 cu
4. on mchcha ngun
in
Vit c cng thc tnhsut in ng v in tr
trong ca b ngun mc(ghp) ni tip, mc (ghp)song song.
Nhn bit c trn s v trong thc t, b ngunmc ni tip hoc mc songsong.
Tnh c sut inng v in tr trongca cc loi b ngunmc ni tip hoc mcsong song. 4 cu
4/3
2 cu 2 cu
5. Phngphp gii biton v mch
in
Vn dng linh hot cccng thc gii cc
bi ton v mch in2 cu2/3
2 cu
6. Thc hnh
Nhn bit c, trn s v trong thc t, b ngunmc ni tip hoc
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S cu 18
S im 10/3T l 33%
S cu: 7
S im: 7/3
S cu 11
S im 11/3
S cu 18
18/3im=60..%
TS 30 s cu10(im)T l 100%
13(13/3 )43 %
17 (17/3 )57 %
30 (10)100 %
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MA TRN KIM TRA HC K I(theo chng trnh chun)
A. Bng trng s
I- T lun
Ch S tit L thuytS tit thc Trng s
LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 13 14
Chng 2: Dng in khng i 14 8 5,6 8,4 15 23
Chng 3: Dng in trong cc mitrng 13 8 5,6 7,4 15 20Tng 37 23 16,1 20,9 43 57
B. Tnh imII- T lun( 5 cu)Thi gian lm bi 45 pht
Bng tnh im, tnh s cuCh s
titL
thuyts tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
Chng 1: in tch in trng 10 7 4,9 5,1 13 14 0 1 0 2Chng 2: Dng in khng i 14 8 5,6 8,4 15 23 1 1 2 2Chng 3: Dng in trong cc mi trng 13 8 5,6 7,4 15 20 1 1 2 2
Tng 37 23 16,1 20,9 43 57 2 3 4 6
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C. Thit k ma trn
1. Ma trn cho t lun
Tn ch Nhn bit(cp 1)
Thng hiu(Cp 2)
Vn dng CngCp 3 Cp 4
Chng 1: in tch in trng (10 tit)1.in tch
nh lutCulng
(1 tit = 4,2%)
Nu c cc cchnhim in mt vt (cxt, tip xc v hngng).
Pht biu cnh lut Cu-lngv ch ra c imca lc in giahai in tch im.
Vn dng c nhlut Cu-lng giic cc bi tp i
vi hai in tchim.
2. Thuytelectrn
(1 tit = 4,2%)
Nu c cc ni dungchnh ca thuytlectron.Pht biu c nh lut
bo ton in tch.
Vn dng cthuyt lectron gii thch cc hintng nhim in
3. in trng(2 tit)= 8,3%
Nu c in trngtn ti u, c tnhcht g.Pht biu c nhngha cng intrng.
4. Cng ca Nu c trng tnh
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lc in(1 tit)= 4,2%
in l trng th.
5. in th(1 tit)= 4,2%
Pht biu c nhngha hiu in th gia
hai im ca in trngv nu c n v ohiu in th.
Nu c miquan h gia
cng intrng u v hiuin th gia haiim ca intrng . Nhn
bit c n vo cng in
trng.
Gii c bi tp vchuyn ng ca mt
in tch dc theong sc ca mtin trng u.
6. T in(1 tit)= 4,2%
Nu c nguyn tccu to ca t in.
Nhn dng c cc tin thng dng.
Pht biu nhngha in dungca t in vnhn bit cn v o indung.
Nu c ngha
cc s ghi trnmi t in.Nu c intrng trong tin v mi intrng u mangnng lng.
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S cu (im)T l %
1(2 im)20%
1(2 im)20%
Chng II. DNG IN KHNG I (11tit)
1.Dng inkhng i
(2 tit)= 8,3%
Nu c dng inkhng i l g.
Nu c sut in ngca ngun in l g.
Nu c cu tochung ca ccngun in hohc (pin, acquy).
2. in nng(2 tit)= 8,3%
Vit c cngthc tnh cngca ngun in :Ang = Eq = EItVit c cngthc tnh cngsut ca ngunin : Png = EI
Vn dng c cngthc Ang = EIt
trong cc bi tp.Vn dng c cngthc Png = EItrong cc bi tp.
3. nh lutm i viton mch
(1tit)= 4,2%
Pht biu c nh lutm i vi ton mch.
Tnh c hiu sutca ngun inVn dng c h
thcE
N
IR r
=+
hoc
U = E Ir gii ccbi tp i vi tonmch, trong mchngoi gm nhiu nht
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l ba in tr.4. on mchcha ngun
in(1 tit = 4,2%)
Vit c cngthc tnh sut inng v in trtrong ca b
ngun mc (ghp)ni tip, mc(ghp) song song.
Nhn bit ctrn s v trongthc t, b ngunmc ni tip hocmc song song.
Tnh c sut inng v in trtrong ca cc loi bngun mc ni tiphoc mc song song.
5. Phng
php gii biton v mch
in(1 tit = 4,2%)
Vn dng linh hot cc
cng thc gii ccbi ton v mch in
6. Thc hnh(2 tit = 8,3%)
Nhn bit c,trn s v trongthc t, b ngun
mc ni tip hocmc song songn gin.
S cu (im)T l %
1(2 im)20%
1(2 im)20%
2(4 im)40%
Chng 3. Dng in trong cc mi trng
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1. Dng introng kim loi Nu c in tr
sut ca kim loi tngtheo nhit .
Nu c hin tngnhit in l g.
Nu c hin tngsiu dn l g.
2.Dng introng cht
in phn
Nu c bn chtca dng in trong
cht in phn.M t c hintng dng cc tan.
Pht biu c nhlut Fa-ra-y v in
phn v vit c hthc ca nh lutny.
Nu c mt s ngdng ca hin tngin phn.
Vn dng nh lutFa-ra-y gii c
cc bi tp n gin vhin tng in phn.
3. Dng introng cht kh
Nu c bn chtca dng in trong
cht kh.
Nu c iu kinto ra tia la in.
Nu c iu kinto ra h quang inv ng dng ca hquang in.
4. Dng introng chnkhng
Nu c iu kin c dng in trongchn khng v c
Nu c dng introng chn khngc ng dng trong
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im v chiu cadng in ny.
cc ng phng int.
5. Dng introng cht bndn
Nu c bn chtca dng in trong
bn dn loi p v bn
dn loi n.Nu c cu to calp chuyn tip p nv tnh cht chnh luca n.
Nu c cu to,cng dng ca it
bn dn v catranzito
6. Thc hnh Tin hnh th nghim xc nh c tnhcht chnh lu ca it
bn dn v c tnhkhuch i catranzito.
S cu (im)T l %
1 cu (2 im)20%
1 cu (2 im)20%
2 cu(4 im)
40%Tng s 2 cu
(4 im) = 40%3 cu
(6 im) = 60%5 cu
(10 im)
kim tra 1 tit hc k 2.Lp 11 theo chng trnh chunHnh thc : (trc nghim, t lun, phi hp)n v : .Bng trng sI- trc nghimCh (chng) s tit L thuyt s tit thc Trng s
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LT VD LT VDChng 4: T trng 6 4 2,8 3,2 23 27
Chng 5: Cm ng in t 6 4 2,8 3,2 23 27
Tng 12 8 5,6 6,4 46 54
II- T lunCh (chng) s tit L thuyt s tit thc Trng s
LT VD LT VDChng 4: T trng 6 4 2,8 3,2 23 27
Chng 5: Cm ng in t 6 4 2,8 3,2 23 27
Tng 12 8 5,6 6,4 46 54
Hnh thc : Trc nghim.Bi kim tra 1 tit hc k 2 mn vt l lp 11 c bn.Bng tnh im, tnh s cuThi gian lm bi 45 pht(30 cu)
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Ch (chng) stit
Lthuyt
s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
Chng 4: T trng 6 4 2,8 3,2 23 27 7 8 2,3 2,7
Chng 5: Cm ng
in t
6 4 2,8 3,2 23 27 7 8 2,3 2,7
Tng 12 8 5,6 6,4 46 54 14 16 4,6 5,4
Hnh thc : T lun.Bi kim tra 1 tit hc k 2 mn vt l lp 11 c bn.Bng tnh im, tnh s cuThi gian lm bi 45pht(Giao bi 45 pht)- 4 cuII- T lun( 4 cu)
Ch (chng) stit
Lthuyt
s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
Chng 4: T trng 6 4 2,8 3,2 23 27 1 1 2,25 2,75
Chng 5: Cm ngin t
6 4 2,8 3,2 23 27 1 1 2,25 2,75
Tng 12 8 5,6 6,4 46 54 2 2 4,5 5,5
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KHUNG MA TRN KIM TRA 45 HC K IIMn: Vt l lp 11
(Thi gian kim tra: 45 pht )Phm vi kim tra: chng 4 + chng 5 chng trnh Chun.
Phng n kim tra: T lun
TnCh
Nhn bit(Cp 1)
Thng hiu(Cp 2)
Vn dngCngCp thp
(Cp 3)Cp cao(Cp 4)
ChngIV: T trng (6 tit)1.T trng(1tit) =8,3%
-Nu c t trng tnti u v c tnh cht
g.- Nu c cc cim ca ng sc tca thanh nam chmthng, ca nam chmch U.
-V c cc ng sct biu din v nu cc
c im ca ng sct ca dng in thngdi, ca ng dy cdng in chy qua vca t trng u.
2. LC T.CM NGT
(2tit)=16.7%
- Pht biu c nh
ngha v nu c phng, chiu ca cmng t ti mt im cat trng. Nu cn v o cm ng t.- Vit c cng thctnh lc t tc dng lnon dy dn c dng
- Xc nh c vect
lc t tc dng ln mton dy dn thng cdng in chy quac t trong ttrng u.
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in chy qua t trongt trng u.
3. T
TRNGCA DNGINCHYTRONGCC DYDN CHNHDNG C
BIT(2 tit)
=16.7%
- Vit c cng thc
tnh cm ng t ti mtim trong t trnggy bi dng in thngdi v hn.- Vit c cng thctnh cm ng t ti mtim trong lng ng dyc dng in chy qua.
- Xc nh c ln,
phng, chiu ca vectcm ng t ti mt imtrong t trng gy bidng in thng di.-Xc nh c ln,
phng, chiu ca vectcm ng t ti mt imtrong lng ng dy cdng in chy qua.
4. LC LO-REN-X
(1 tit)
=8.3%
- Nu c lc Lo-ren-xl g v vit c cngthc tnh lc ny.- Xc nh c cng, phng, chiu calc Lo-ren-x tc dng
ln mt in tch qchuyn ng vi vn tcv trong mt phngvung gc vi ccng sc ca t trngu.
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S cu:T l%
1 cu (2,25)22,5%
1 cu (2.75)27,5%
2cu( 5,0)
50%Chng V.CM NG IN T
1. TTHNG.
CM NGIN T
(2 tit)=16.7%
-Vit c cng thctnh t thng qua mtdin tch v nu cn v o t thng. Nuc cc cch lm bini t thng.- M t c th nghimv hin tng cm ngin t.
- Nu c dng inFu-c l g.
- Lm c th nghimv hin tng cm ngin t.- Xc nh c chiuca dng in cm ngtheo nh lut Len-x.
2. SUTIN
NG CM
NG(2 tit)=16.7%
Pht biu c nh lutFa-ra-y v cm ngin t.
Tnh c sut inng cm ng trongtrng hp t thng quamt mch bin i utheo thi gian trong cc
bi ton:
Tnh c sutin ng cmng trongtrng hp tthng qua mtmch bin iu theo thigian trong cc
bi ton:
3. T CMNu c t cm lg v n v o t
Tnh c sut inng t cm trong ng
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(2 tit)=16.7%
cm.Nu c hin tng tcm l g.
dy khi dng in chyqua n c cng
bin i u theo thigian.
Nu c t trng
trong lng ng dy cdng in chy qua vmi t trng u mangnng lng.
S cu:T l%
1 cu (2,25)22,5%
1 cu (2.75)27,5%
2cu ( 5,0)50%
Tng s cu(im)
T l %
2 cu(4,5)
45 %
2 cu(5.5)
55%
4cu( 10)
100 %
Ma trn cho trc nghimKHUNG MA TRN KIM TRA
(Bng m t cc tiu ch ca kim tra)Mn: Vt l lp 11 THPT, chng trnh Chun
(Thi gian: 45 pht, 30 cu trc nghim)
Phm vi kim tra: Chng 4. T trng; Chng 5. Cm ng in t
Tn Ch Nhn bit(Cp 1)
Thng hiu(Cp 2)
Vn dng
CngCp thp(Cp 3)
Cp cao(Cp 4)
Chng 4. Ttrng
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1. T trng -Nu c t trng tn ti u v c tnh cht g.- Nu c cc c imca ng sc t ca thanhnam chm thng, ca nam
chm ch U.(1 cu)
-V c cc ng sct biu din v nu ccc im ca ng sct ca dng in thngdi, ca ng dy c dng
in chy qua v ca ttrng u.(2cu )
8 cu - 8/3
2. Lc t.Cm ng t
- Pht biu c nh nghav nu c phng, chiuca cm ng t ti mtim ca t trng. Nuc n v o cm ng t.- Vit c cng thc tnhlc t tc dng ln on dydn c dng in chy quat trong t trng u.
(2 cu)
- Xc nh c vect lc t tc dng ln mton dy dn thng c dng in chy qua ct trong t trng u.(3 cu)
3. T trngca dng inchy trongdy dn chnh dng cbit
- Vit c cng thc tnhcm ng t ti mt imtrong t trng gy bidng in thng di v hn.- Vit c cng thc tnhcm ng t ti mt imtrong lng ng dy c dng
- Xc nh c ln,phng, chiu ca vectcm ng t ti mt imtrong t trng gy bidng in thng di.-Xc nh c ln,
phng, chiu ca vect4 cu 4/3
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in chy qua.
(1 cu)
cm ng t ti mt imtrong lng ng dy cdng in chy qua.
(3 cu)4. Lc Lo-
ren- x
- Nu c lc Lo-ren-x l
g v vit c cng thctnh lc ny.- Xc nh c cng ,
phng, chiu ca lc Lo-ren-x tc dng ln mtin tch q chuyn ng vivn tc v trong mt phngvung gc vi cc ngsc ca t trng u.
(3 cu)
3 cu - 1
S cu 15
S im 5
T l 50%
S cu 7
S im 2,3
S cu: 8
S im: 2,7
S cu 15
5,0 = 50%
Chng 5. Cm ng in t1. TTHNG.CM NGIN T
-Vit c cng thc tnht thng qua mt din tchv nu c n v o tthng. Nu c cc cchlm bin i t thng.
- Lm c th nghimv hin tng cm ngin t.- Xc nh c chiuca dng in cm ng
5cu 5/3
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- M t c th nghim vhin tng cm ng in t.- Nu c dng in Fu-cl g.
(3 cu)
theo nh lut Len-x.
(2 cu)
2. SUTIN NGCM NG
Pht biu c nh lut Fa-ra-y v cm ng in t.(2 cu)
Tnh c sut inng cm ng trongtrng hp t thngqua mt mch bin iu theo thi giantrong cc bi ton:++
(3 cu)
5 cu - 5/3
3. T CM Nu c t cm l g vn v o t cm.
Nu c hin tng tcm l g.
(2 cu)
Tnh c sut inng t cm trong ng
dy khi dng in chyqua n c cng bini u theo thi gian.
Nu c t trngtrong lng ng dy cdng in chy qua vmi t trng u mangnng lng.
5 cu - 5/3
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(3 cu)
S cu 15
S im 5.
T l 50%
S cu: 7
S im: 7/3
S cu 8
S im 8/3
S cu 15
5im=50%
TS 30 s cu10(im)T l 100%
14(14/3 )46 %
16(16/3 )54 %
30 (10)100 %
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MA TRN KIM TRA HC K II(theo chng trnh chun)
A. Bng trng s
I- T lun
Ch S tit L thuytS tit thc Trng s
LT VD LT VD
Chng IV. T trng 6 4 2,8 3,2 9 10
Chng V. Cm ng in t 6 4 2,8 3,29 10
Chng VI. Khc x nh sng 4 2 1,4 2,6 5 8
Chng VII. Mt. Cc dng c quang 15 9 5,6 9,4 18 31
Tng 31 19 12,6 18,4 41 59
B. Tnh imII- T lun( 6 cu)Thi gian lm bi 45 pht
Bng tnh im, tnh s cuCh s
titL
thuyts tit thc Trng s S cu im sLT VD LT VD LT VD LT VD
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Chng IV. T trng 6 4 2,8 3,2 9 10 1 1,75Chng V. Cm ng in t 6 4 2,8 3,2 9 10 1 1,75Chng VI. Khc x nh sng 4 2 1,4 2,6 5 8 1 1,75Chng VII. Mt. Cc dng c quang 15 9 5,6 9,4 18 31 1 2 1,75 3
Tng 31 19 12,6 18,4 41 59 2 4 3,5 6,5
C. Thit k ma trn
1. Ma trn cho t lun
Tn ch Nhn bit(cp 1)
Thng hiu(Cp 2)
Vn dng CngCp 3 Cp 4
Chng IV. T trng1. T trng 1. T trng l g? 1. Nu c t
trng tn ti u v c tnh cht
g.2. Nu c ccc im cang sc t cathnh nam chmthng v ca namchm ch U.
1. V c cc ngsc t biu din vnu c cc c
im ca ng sct ca dng inthng di v ca ngdy c dng inchy qua v ca ttrng u.
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2. Lc t vcm ng t.
1. Pht biu c nhngha cm ng t.2. c im vc t cmng t.
1. Nm c quytc bn tay tridng xc nhchiu lc t. Vquy tc nm tay
phi xc nhchiu ng sct.2. Vit c cngthc tnh lc t tcdng ln on dydn c dng inchy qua t trongt trng u.
1. Xc nh c vect lc t tc dng lnmt on dy dnthng c dng inchy qua c t
trong t trng u.
1. Xc nh c lc ttng hp ti 1 im.2. Tm tp hp cc imm ti c lc t tnghp trit tiu.
3. Cn bng ca mtdng in trong ttrng.
3. T trngca dng inchy trong ccdy dn c hnhdng c bit.
1. Vit c cng thctnh cm ng t ti mtim trong t trnggy ra bi dng inthng v di v hn.2. Vit c cng thctnh cm ng t ti mtim trong lng ng dyc dng in chy qua.
1. Xc nh c ln, phng, chiuca vec t cm ng tti mt im trong ttrng gy ra bidng in thng di.2. Xc nh c ln, phng, chiuca vec t cm ng tti mt im tronglng ng dy c dngin chy qua.
1. Xc nh c cmng t tng hp ti 1im.2. Tm tp hp cc imm ti c cm ngt tng hp trit tiu.
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4. Lc Lo-ren-x
1. Nu c lc Lo-ren-x l g v vit ccng thc tnh lc ny.
1. S dng cquy tc bn taytri dng xcnh chiu lc Lo-ren-x.
1. Xc nh ccng , phng,chiu ca lc Lo-ren-x tc dng ln mtin tch q chuyn
ng vi vn tcv
trong mt phngvung gc vi ccng sc t ca ttrng u.
1. Gii c bi ton tl gia lc Lo-ren-xv vn tc ht.
S cu
T l
1 cu ( 1,75 im) = 16,7% 1 cu(1,75 im)
= 16,7%Chng V. Cm ng in t
1. Sut inng cm ng
1. Pht biu c nhlut Fa-ra-y v cmng in t. Biu thc.
1. Tnh c sutin ng cm ngtrong trng hp tthng qua mch bini u theo thi giantrong cc bi ton.
2. Sut inng cm ng 1. Pht biu c nhlut Fa-ra-y v cmng in t. Biu thc.
1. Tnh c sutin ng cm ngtrong trng hp tthng qua mch bini u theo thi giantrong cc bi ton.
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3. T cm 1. Nu c t cml g v n v o tcm.2. Nu c hin tngt cm l g.3. Nu c t trngtrong lng ng dy cdng in chy qua vmi t trng u mangnng lng.
1. Tnh c sutin ng t cmtrong ng dy khidng in chy quan c cng bini u theo thigian.
S cu
T l
1 cu ( 1,75 im) = 16,7% 1 cu( 1,75 im)
= 16,7%Chng VI. Khc x nh sng
7. Khc xnh sng
1. Nu c hin tngkhc x. V d.2. Bit tia sng tuynthng v ch b lch khitruyn xin gc qua haimi trng trong sutkhc nhau.
3. Hiu s lin quangia chit sut v tc truyn nh sng trongcc mi trng.4. Pht biu c nhlut khc x nh sng vvit c h thc canh lut ny.
1. Nu n21 > 1 th r< i v n21 < 1 th r> i2. V c ngi tia sng thunv nghch.3. Phn tch c
hnh v v tiakhc x v thitlp c mi quanh gia gc ti,gc khc x cngnh chit sut cahai mi trng.4. Bit c mi
1. Bit tnh chit sut,gc ti, gc khc xtrong cc h thc canh lut khc x.2. Tnh c vn tcca tia sng khi iqua cc mi trng
trong sut khc nhau.3. Gii thch c vsao mt ngi quanst thy mi vt xungquanh. ra phng
php tng hnh .
(Ch xt bi ton c
1. Gii c bi tonlp t l chit sut giacc mi trng.2. Vn dng cng thcnh lut khc x kthp vi kin thc tonhc nh tam gic ng
dng, tam gic vung tm su mc chtlng da vo khc x.
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5. Bit c cc khinim: tia ti, tia khc x,tia phn x cng nhgc ti, gc khc x vgc phn x, chit sut,chit sut t i, chitsut tuyt i.6. Nu c tnh chtthun nghch ca struyn nh sng v ch ras th hin tnh cht ny nh lut khc x nhsng.
lin quan gia gcti v gc khcx. Cng nh sinca n.
ti a hai ln khc xca tia sng trn mtng truyn).
2. Phn x
ton phn
1. M t c hin
tng phn x tonphn.2. Nu c 2 iu kin c phn x ton phn,
biu thc.
1. Bit nhn dng
cc trng hpxy ra hin tngphn x ton phnca tia sng khiqua mt phncch.2. Hiu cnguyn tc cu toca cp quang,
phng php nisoi, truyn dn tnhiu (thng tin).Cp quang c uim hn so vicp kim loi ltruyn c lngd liu rt ln,
1. Bit dng iu kin
xy ra phn x tonphn xc nh cctrng hp xy ra
phn x ton phn khitia sng i qua mt
phn cch cc mitrng trong sut.
1. Gii c bi ton
v phn x ton phnkt hp vi hnh hc(o bng , gc giihn nh nht bao nhiu khng c khcx,...).
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khng b nhiu bitrng in t bnngoi.3. Gii thch chin tng o nh.4. Nguyn tc tnghnh.
S cu
T l
1 cu ( 1,75 im) = 16,7% 1 cu(1,75 im)= 16,7%
Chng VII. Mt. Cc dng c quang
1. Lng knh 1. Lng knh l g? Nuc tnh cht ca lngknh lm lch tia sngtruyn qua n.2. Nm c cc khinim: gc ti, gc l,gc lch, gc khc x,gc chit quang, tia ti,tia l, tia khc x.3. V c ng
truyn tia sng qua lngknh.
1. V c tiasng qua lngknh.
1. Vn dng c cccng thc ca lngknh tm gc l,gc lch v chitsut.
1. Bi ton iu kin c tia l v khng c tial qua lng knh.
3 cu
2. Thu knhmng.
1. Nu c cc khinim: Thu knh mng,cc loi thu knh, trcchnh, trc ph, quangtm, tiu im vt chnhF, tiu im nh chnh
1. Nm c ccquy tc tia sngqua tiu im F,F, F1, F2... vc ngtruyn tia sng qua
1. Vn dng cc cngthc v thu knh gii c cc bi tpn gin:-Tm v tr vt, nh(da trn tiu c f v
1. Bi ton v s dichuyn ca thu knh,vt v nh.2. Thu knh ghp.
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F, tiu im vt ph F1,tiu im nh ph F1.Tiu din, tiu c f,khong cch t vt tithu knh d v khongcch t nh ti thu knhd.2. Nm c cc cngthc tm v tr vt, nh:
d.d '
'f
d d=
+
'.
'
d fd
d f=
.'
d fd
d f=
3. Nu c nh ngha
t v biu thc:1D
f= (lu i n v
f)4. Nu c nh nghas phng i ca nh to
bi thu knh?'d
kd
=
5. Nm c quy c v
du ca f, d, d, k.
thu knh hi t,phn k v h haithu knh ngtrc.
da trn khong cchca vt v nh L hoc phng i k)2. Dng c nh cavt l im sng Shoc l vt phng nhAB vung gc vitrc chnh ca thuknh qua thu knh hit hay phn k.3. S quy tc 3 imthng hng O, S, Shoc M, S, F dng v xc nh loi
thu knh.
( 5,25 im)
3. Mt 1. Bit c cu to camt.2. im cc vin, imcc cn.3. Nng sut phn li camt.4. Cc tt ca mt v
1. Nu c siu tit ca mtkhi nhn vt im cc cn v im cc vin.2. Nu c gctrng v nng sut
1. Bi ton sa tt mtcn th v vin th.2. Bi ton xc nhim cc cn v imcc vin.3. Phm vi t vt khikhng eo knh.
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cch khc phc. phn li l g.3. Trnh by ccc im ca mtcn, mt vin, mtlo v mt quanghc v nu tcdng ca knh cneo khc phccc tt ny.4. Nu c slu nh trn mngli l g v nuc v d thc tng dng hin
tng ny.4. Knh lp 1. Bit k hiu 3x, 5x,8x... ghi trn knh lp.2. Bit khi nim gctrng nh v gc trngvt.
1. Nu cnguyn tc cu tov cng dng caknh lp.2. Trnh by cs bi gic canh to bi knhlp.
3. Cch ngmchng v cc vngm chng im cc cn.
1. V c nh cavt tht to bi knhlp v gii thch tcdng tng gc trngnh ca knh.
1. Xc nh phm vingm chng mt vtqua knh lp.2.Tm s bi gic.
5. Knh hin vi 1. Bit khi nim vtknh v th knh, diquang hc ca knh hinvi.
1. Nu cnguyn tc cu tov cng dng caknh hin vi.
1. V c nh cavt tht to bi knhhin vi v gii thchtc dng tng gc
1. Xc nh phm vingm chng mt vtqua knh hin vi.2.Tm s bi gic.
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2. Trnh by cs bi gic canh to bi knhhin vi.
trng nh ca knh.
6. Knh thinvn
1. Bit khi nim vtknh v th knh ca knhhin vi.
1. Nu cnguyn tc cu tov cng dng caknh thin vn.2. Trnh by cs bi gic canh to bi knhthin vn l g.
1. V c nh cavt tht c to biknh thin vn v giithch tc dng tnggc trong nh caknh
1. Xc nh phm vingm chng mt vtqua knh hin thin vn.2.Tm s bi gic.
7. Thc hnh 1. Xc nh c tiuc ca thu knh phn
k bng th nghim.S cu
T l
1 cu ( 1,75 im) = 16,7% 2 cu ( 3,5im) = 33%
Tng s cu
T l
2 cu ( 3,5 im) = 33% 4 cu ( 6,5 im) = 67% 6 cu( 10 im)
100%
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