Ma Tran Kiem Tra Ly 11 Tron Bo

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    kim tra 1 titHc k I lp 11 theo chng trnh chun

    A. Bng trng sI- trc nghim

    Ch

    S tit L thuytS tit thc Trng s

    LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 20 21

    Chng 2: Dng in khng i 14 8 5,6 8,4 24 35

    Tng 24 15 10,5 13,5 44 56

    II- T lun

    Ch S tit L thuytS tit thc Trng s

    LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 20 21

    Chng 2: Dng in khng i 14 8 5,6 8,4 24 35

    Tng 24 15 10,5 13,5 44 56

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    B. Tnh im

    .I- trc nghim khch quan

    ( 30 cu)Thi gian lm bi 45 phtBng tnh im, tnh s cu

    Ch stit

    Lthuyt

    s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 20 21 6 6 2 2Chng 2: Dng in khng i 14 8 5,6 8,4 24 35 7 11 2.4 3.6Tng 24 15 10,5 13,5 44 56 13 17 4.4 5.6

    II- T lun( 5 cu)Thi gian lm bi 45 phtBng tnh im, tnh s cu

    Ch stit

    Lthuyt

    s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 20 21 1 1 2 2Chng 2: Dng in khng i 14 8 5,6 8,4 24 35 1 2 2 4Tng 24 15 10,5 13,5 44 56 2 3 4 6

    C. Thit k ma trn1. Ma trn cho t lun

    Tn ch Nhn bit(cp 1)

    Thng hiu(Cp 2)

    Vn dng CngCp 3 Cp 4

    Chng 1: in tch in trng (10 tit)1.in tch

    nh lutNu c cc cchnhim in mt vt (c

    Pht biu cnh lut Cu-lng

    Vn dng c nhlut Cu-lng gii

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    Culng(1 tit = 4,2%)

    xt, tip xc v hngng).

    v ch ra c imca lc in giahai in tch im.

    c cc bi tp ivi hai in tchim.

    2. Thuyt

    electrn(1 tit = 4,2%)

    Nu c cc ni dung

    chnh ca thuytlectron.Pht biu c nh lut

    bo ton in tch.

    Vn dng c

    thuyt lectron gii thch cc hintng nhim in

    3. in trng(2 tit)= 8,3%

    Nu c in trngtn ti u, c tnhcht g.Pht biu c nhngha cng intrng.

    4. Cng calc in

    (1 tit)= 4,2%

    Nu c trng tnhin l trng th.

    5. in th(1 tit)= 4,2%

    Pht biu c nhngha hiu in th giahai im ca in trngv nu c n v ohiu in th.

    Nu c miquan h giacng intrng u v hiuin th gia haiim ca intrng . Nhn

    Gii c bi tp vchuyn ng ca mtin tch dc theong sc ca mtin trng u.

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    bit c n vo cng intrng.

    6. T in(1 tit)= 4,2%

    Nu c nguyn tccu to ca t in.

    Nhn dng c cc tin thng dng.

    Pht biu nhngha in dungca t in vnhn bit cn v o indung.

    Nu c nghacc s ghi trnmi t in.

    Nu c in

    trng trong tin v mi intrng u mangnng lng.

    S cu (im)T l %

    1(2 im)20%

    1(2 im)20%

    2(4 im)40%

    Chng II. DNG IN KHNG I (11tit)

    1.Dng inkhng i

    (2 tit)= 8,3%

    Nu c dng inkhng i l g.

    Nu c sut in ngca ngun in l g.

    Nu c cu tochung ca ccngun in hohc (pin, acquy).

    2. in nng Vit c cng

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    (2 tit)= 8,3% thc tnh cngca ngun in :Ang = Eq = EItVit c cngthc tnh cng

    sut ca ngunin : Png = EI

    Vn dng c cngthc Ang = EIttrong cc bi tp.Vn dng c cng

    thc Png = EItrong cc bi tp.

    3. nh lutm i viton mch

    (1tit)= 4,2%

    Pht biu c nh lutm i vi ton mch.

    Tnh c hiu sutca ngun inVn dng c h

    thcE

    N

    IR r

    =+

    hoc

    U = E Ir gii ccbi tp i vi tonmch, trong mchngoi gm nhiu nhtl ba in tr.

    4. on mchcha ngun

    in(1 tit = 4,2%)

    Vit c cngthc tnh sut in

    ng v in trtrong ca bngun mc (ghp)ni tip, mc(ghp) song song.

    Nhn bit ctrn s v trongthc t, b ngun

    Tnh c sut inng v in trtrong ca cc loi bngun mc ni tiphoc mc song song.

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    mc ni tip hocmc song song.

    5. Phngphp gii biton v mch

    in(1 tit = 4,2%)

    Vn dng linh hot cccng thc gii cc

    bi ton v mch in

    6. Thc hnh(2 tit = 8,3%)

    Nhn bit c,trn s v trongthc t, b ngunmc ni tip hocmc song song

    n gin.S cu

    (im)T l %

    1(2 im)20%

    2(4im)40%

    3(6im)60%

    Tng s cu(im)T l %

    2(4 im)40%

    3(6im)60%

    5(10 im)100%

    Ma trn cho trc nghimKHUNG MA TRN KIM TRA

    (Bng m t cc tiu ch ca kim tra)Mn: Vt l lp 11 THPT, chng trnh Chun

    (Thi gian: 45 pht, 30 cu trc nghim)Phm vi kim tra: Chng 1. in tch in trng; Chng 2. Dng in khng i..

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    Tn Ch Nhn bit

    (Cp 1)

    Thng hiu

    (Cp 2)

    Vn dng

    CngCp thp

    (Cp 3)

    Cp cao

    (Cp 4)

    Chng 1. in tch in trng

    1 in tch nh lut Cu-

    lng

    Nu c cccch nhimin mt vt(c xt, tip

    xc v hngng).

    Pht biu c nh lutCu-lng v ch ra c imca lc in gia hai intch im.

    Vn dng c nh lutCu-lng gii c cc

    bi tp i vi hai intch im.

    5 cu5/3

    1 cu 1 cu 3 cu

    2. Thuyt

    electrn

    Nu c ccni dung chnh

    ca thuytlectron.Pht biu cnh lut boton in tch.

    Vn dng c thuytlectron gii thch cc

    hin tng nhim in

    2 cu2/3

    2 cu

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    3. in trngNu c intrng tn ti u, c tnhcht g.

    Pht biu cnh nghacng intrng.

    1 cu1/3

    1cu

    4. Cng calc in

    Nu ctrng tnh

    in l trngth. 1 cu

    1/3

    1cu

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    5. in thPht biu cnh nghahiu in thgia hai imca in

    trng v nuc n v ohiu in th.

    Nu c mi quan h giacng in trng uv hiu in th gia haiim ca in trng .

    Nhn bit c n v ocng in trng.

    Gii c bi tp vchuyn ng ca mtin tch dc theo ngsc ca mt in trng

    u.

    2 cu2/3

    1cu 1cu

    6. T in Nu cnguyn tc cuto ca t in.

    Nhn dng

    c cc tin thngdng.

    Pht biu nh ngha indung ca t in v nhn

    bit c n v o indung.

    Nu c ngha cc s ghi

    trn mi t in.Nu c in trng trongt in v mi in trngu mang nng lng.

    1 cu1/3

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    1 cu

    Chng 1.S cu 12

    S im 4T l 40%

    S cu 6S im 2

    S cu: 6S im: 2

    S cu 12 .4,0im=40%

    Chng 2. Dng in khng i

    1.Dng in

    khng i

    Nu c

    dng inkhng i lg.

    Nu c sutin ng cangun in lg.

    Nu c cu to chung ca

    cc ngun in ho hc(pin, acquy).

    2 cu2/3

    2 cu

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    2. in nng Vit c cng thc tnhcng ca ngun in : Ang= Eq = EItVit c cng thc tnhcng sut ca ngun in :

    Png = EI

    Vn dng c cngthc Ang = EIttrong cc bi tp.Vn dng c cngthc Png = EItrong cc bi tp.

    5 cu5/3

    2 cu3 cu

    3. nh lutm i viton mch

    Pht biu cnh lut mi vi tonmch.

    Tnh c hiu sut cangun inVn dng c h thc

    E

    N

    IR r

    =+

    hoc U = E

    Ir gii cc bi tp ivi ton mch, trong mch ngoi gm nhiunht l ba in tr.

    5 cu5/3

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    1 cu 4 cu

    4. on mchcha ngun

    in

    Vit c cng thc tnhsut in ng v in tr

    trong ca b ngun mc(ghp) ni tip, mc (ghp)song song.

    Nhn bit c trn s v trong thc t, b ngunmc ni tip hoc mc songsong.

    Tnh c sut inng v in tr trongca cc loi b ngunmc ni tip hoc mcsong song. 4 cu

    4/3

    2 cu 2 cu

    5. Phngphp gii biton v mch

    in

    Vn dng linh hot cccng thc gii cc

    bi ton v mch in2 cu2/3

    2 cu

    6. Thc hnh

    Nhn bit c, trn s v trong thc t, b ngunmc ni tip hoc

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    S cu 18

    S im 10/3T l 33%

    S cu: 7

    S im: 7/3

    S cu 11

    S im 11/3

    S cu 18

    18/3im=60..%

    TS 30 s cu10(im)T l 100%

    13(13/3 )43 %

    17 (17/3 )57 %

    30 (10)100 %

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    MA TRN KIM TRA HC K I(theo chng trnh chun)

    A. Bng trng s

    I- T lun

    Ch S tit L thuytS tit thc Trng s

    LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 13 14

    Chng 2: Dng in khng i 14 8 5,6 8,4 15 23

    Chng 3: Dng in trong cc mitrng 13 8 5,6 7,4 15 20Tng 37 23 16,1 20,9 43 57

    B. Tnh imII- T lun( 5 cu)Thi gian lm bi 45 pht

    Bng tnh im, tnh s cuCh s

    titL

    thuyts tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

    Chng 1: in tch in trng 10 7 4,9 5,1 13 14 0 1 0 2Chng 2: Dng in khng i 14 8 5,6 8,4 15 23 1 1 2 2Chng 3: Dng in trong cc mi trng 13 8 5,6 7,4 15 20 1 1 2 2

    Tng 37 23 16,1 20,9 43 57 2 3 4 6

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    C. Thit k ma trn

    1. Ma trn cho t lun

    Tn ch Nhn bit(cp 1)

    Thng hiu(Cp 2)

    Vn dng CngCp 3 Cp 4

    Chng 1: in tch in trng (10 tit)1.in tch

    nh lutCulng

    (1 tit = 4,2%)

    Nu c cc cchnhim in mt vt (cxt, tip xc v hngng).

    Pht biu cnh lut Cu-lngv ch ra c imca lc in giahai in tch im.

    Vn dng c nhlut Cu-lng giic cc bi tp i

    vi hai in tchim.

    2. Thuytelectrn

    (1 tit = 4,2%)

    Nu c cc ni dungchnh ca thuytlectron.Pht biu c nh lut

    bo ton in tch.

    Vn dng cthuyt lectron gii thch cc hintng nhim in

    3. in trng(2 tit)= 8,3%

    Nu c in trngtn ti u, c tnhcht g.Pht biu c nhngha cng intrng.

    4. Cng ca Nu c trng tnh

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    lc in(1 tit)= 4,2%

    in l trng th.

    5. in th(1 tit)= 4,2%

    Pht biu c nhngha hiu in th gia

    hai im ca in trngv nu c n v ohiu in th.

    Nu c miquan h gia

    cng intrng u v hiuin th gia haiim ca intrng . Nhn

    bit c n vo cng in

    trng.

    Gii c bi tp vchuyn ng ca mt

    in tch dc theong sc ca mtin trng u.

    6. T in(1 tit)= 4,2%

    Nu c nguyn tccu to ca t in.

    Nhn dng c cc tin thng dng.

    Pht biu nhngha in dungca t in vnhn bit cn v o indung.

    Nu c ngha

    cc s ghi trnmi t in.Nu c intrng trong tin v mi intrng u mangnng lng.

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    S cu (im)T l %

    1(2 im)20%

    1(2 im)20%

    Chng II. DNG IN KHNG I (11tit)

    1.Dng inkhng i

    (2 tit)= 8,3%

    Nu c dng inkhng i l g.

    Nu c sut in ngca ngun in l g.

    Nu c cu tochung ca ccngun in hohc (pin, acquy).

    2. in nng(2 tit)= 8,3%

    Vit c cngthc tnh cngca ngun in :Ang = Eq = EItVit c cngthc tnh cngsut ca ngunin : Png = EI

    Vn dng c cngthc Ang = EIt

    trong cc bi tp.Vn dng c cngthc Png = EItrong cc bi tp.

    3. nh lutm i viton mch

    (1tit)= 4,2%

    Pht biu c nh lutm i vi ton mch.

    Tnh c hiu sutca ngun inVn dng c h

    thcE

    N

    IR r

    =+

    hoc

    U = E Ir gii ccbi tp i vi tonmch, trong mchngoi gm nhiu nht

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    l ba in tr.4. on mchcha ngun

    in(1 tit = 4,2%)

    Vit c cngthc tnh sut inng v in trtrong ca b

    ngun mc (ghp)ni tip, mc(ghp) song song.

    Nhn bit ctrn s v trongthc t, b ngunmc ni tip hocmc song song.

    Tnh c sut inng v in trtrong ca cc loi bngun mc ni tiphoc mc song song.

    5. Phng

    php gii biton v mch

    in(1 tit = 4,2%)

    Vn dng linh hot cc

    cng thc gii ccbi ton v mch in

    6. Thc hnh(2 tit = 8,3%)

    Nhn bit c,trn s v trongthc t, b ngun

    mc ni tip hocmc song songn gin.

    S cu (im)T l %

    1(2 im)20%

    1(2 im)20%

    2(4 im)40%

    Chng 3. Dng in trong cc mi trng

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    1. Dng introng kim loi Nu c in tr

    sut ca kim loi tngtheo nhit .

    Nu c hin tngnhit in l g.

    Nu c hin tngsiu dn l g.

    2.Dng introng cht

    in phn

    Nu c bn chtca dng in trong

    cht in phn.M t c hintng dng cc tan.

    Pht biu c nhlut Fa-ra-y v in

    phn v vit c hthc ca nh lutny.

    Nu c mt s ngdng ca hin tngin phn.

    Vn dng nh lutFa-ra-y gii c

    cc bi tp n gin vhin tng in phn.

    3. Dng introng cht kh

    Nu c bn chtca dng in trong

    cht kh.

    Nu c iu kinto ra tia la in.

    Nu c iu kinto ra h quang inv ng dng ca hquang in.

    4. Dng introng chnkhng

    Nu c iu kin c dng in trongchn khng v c

    Nu c dng introng chn khngc ng dng trong

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    im v chiu cadng in ny.

    cc ng phng int.

    5. Dng introng cht bndn

    Nu c bn chtca dng in trong

    bn dn loi p v bn

    dn loi n.Nu c cu to calp chuyn tip p nv tnh cht chnh luca n.

    Nu c cu to,cng dng ca it

    bn dn v catranzito

    6. Thc hnh Tin hnh th nghim xc nh c tnhcht chnh lu ca it

    bn dn v c tnhkhuch i catranzito.

    S cu (im)T l %

    1 cu (2 im)20%

    1 cu (2 im)20%

    2 cu(4 im)

    40%Tng s 2 cu

    (4 im) = 40%3 cu

    (6 im) = 60%5 cu

    (10 im)

    kim tra 1 tit hc k 2.Lp 11 theo chng trnh chunHnh thc : (trc nghim, t lun, phi hp)n v : .Bng trng sI- trc nghimCh (chng) s tit L thuyt s tit thc Trng s

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    LT VD LT VDChng 4: T trng 6 4 2,8 3,2 23 27

    Chng 5: Cm ng in t 6 4 2,8 3,2 23 27

    Tng 12 8 5,6 6,4 46 54

    II- T lunCh (chng) s tit L thuyt s tit thc Trng s

    LT VD LT VDChng 4: T trng 6 4 2,8 3,2 23 27

    Chng 5: Cm ng in t 6 4 2,8 3,2 23 27

    Tng 12 8 5,6 6,4 46 54

    Hnh thc : Trc nghim.Bi kim tra 1 tit hc k 2 mn vt l lp 11 c bn.Bng tnh im, tnh s cuThi gian lm bi 45 pht(30 cu)

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    Ch (chng) stit

    Lthuyt

    s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

    Chng 4: T trng 6 4 2,8 3,2 23 27 7 8 2,3 2,7

    Chng 5: Cm ng

    in t

    6 4 2,8 3,2 23 27 7 8 2,3 2,7

    Tng 12 8 5,6 6,4 46 54 14 16 4,6 5,4

    Hnh thc : T lun.Bi kim tra 1 tit hc k 2 mn vt l lp 11 c bn.Bng tnh im, tnh s cuThi gian lm bi 45pht(Giao bi 45 pht)- 4 cuII- T lun( 4 cu)

    Ch (chng) stit

    Lthuyt

    s tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

    Chng 4: T trng 6 4 2,8 3,2 23 27 1 1 2,25 2,75

    Chng 5: Cm ngin t

    6 4 2,8 3,2 23 27 1 1 2,25 2,75

    Tng 12 8 5,6 6,4 46 54 2 2 4,5 5,5

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    KHUNG MA TRN KIM TRA 45 HC K IIMn: Vt l lp 11

    (Thi gian kim tra: 45 pht )Phm vi kim tra: chng 4 + chng 5 chng trnh Chun.

    Phng n kim tra: T lun

    TnCh

    Nhn bit(Cp 1)

    Thng hiu(Cp 2)

    Vn dngCngCp thp

    (Cp 3)Cp cao(Cp 4)

    ChngIV: T trng (6 tit)1.T trng(1tit) =8,3%

    -Nu c t trng tnti u v c tnh cht

    g.- Nu c cc cim ca ng sc tca thanh nam chmthng, ca nam chmch U.

    -V c cc ng sct biu din v nu cc

    c im ca ng sct ca dng in thngdi, ca ng dy cdng in chy qua vca t trng u.

    2. LC T.CM NGT

    (2tit)=16.7%

    - Pht biu c nh

    ngha v nu c phng, chiu ca cmng t ti mt im cat trng. Nu cn v o cm ng t.- Vit c cng thctnh lc t tc dng lnon dy dn c dng

    - Xc nh c vect

    lc t tc dng ln mton dy dn thng cdng in chy quac t trong ttrng u.

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    in chy qua t trongt trng u.

    3. T

    TRNGCA DNGINCHYTRONGCC DYDN CHNHDNG C

    BIT(2 tit)

    =16.7%

    - Vit c cng thc

    tnh cm ng t ti mtim trong t trnggy bi dng in thngdi v hn.- Vit c cng thctnh cm ng t ti mtim trong lng ng dyc dng in chy qua.

    - Xc nh c ln,

    phng, chiu ca vectcm ng t ti mt imtrong t trng gy bidng in thng di.-Xc nh c ln,

    phng, chiu ca vectcm ng t ti mt imtrong lng ng dy cdng in chy qua.

    4. LC LO-REN-X

    (1 tit)

    =8.3%

    - Nu c lc Lo-ren-xl g v vit c cngthc tnh lc ny.- Xc nh c cng, phng, chiu calc Lo-ren-x tc dng

    ln mt in tch qchuyn ng vi vn tcv trong mt phngvung gc vi ccng sc ca t trngu.

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    S cu:T l%

    1 cu (2,25)22,5%

    1 cu (2.75)27,5%

    2cu( 5,0)

    50%Chng V.CM NG IN T

    1. TTHNG.

    CM NGIN T

    (2 tit)=16.7%

    -Vit c cng thctnh t thng qua mtdin tch v nu cn v o t thng. Nuc cc cch lm bini t thng.- M t c th nghimv hin tng cm ngin t.

    - Nu c dng inFu-c l g.

    - Lm c th nghimv hin tng cm ngin t.- Xc nh c chiuca dng in cm ngtheo nh lut Len-x.

    2. SUTIN

    NG CM

    NG(2 tit)=16.7%

    Pht biu c nh lutFa-ra-y v cm ngin t.

    Tnh c sut inng cm ng trongtrng hp t thng quamt mch bin i utheo thi gian trong cc

    bi ton:

    Tnh c sutin ng cmng trongtrng hp tthng qua mtmch bin iu theo thigian trong cc

    bi ton:

    3. T CMNu c t cm lg v n v o t

    Tnh c sut inng t cm trong ng

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    (2 tit)=16.7%

    cm.Nu c hin tng tcm l g.

    dy khi dng in chyqua n c cng

    bin i u theo thigian.

    Nu c t trng

    trong lng ng dy cdng in chy qua vmi t trng u mangnng lng.

    S cu:T l%

    1 cu (2,25)22,5%

    1 cu (2.75)27,5%

    2cu ( 5,0)50%

    Tng s cu(im)

    T l %

    2 cu(4,5)

    45 %

    2 cu(5.5)

    55%

    4cu( 10)

    100 %

    Ma trn cho trc nghimKHUNG MA TRN KIM TRA

    (Bng m t cc tiu ch ca kim tra)Mn: Vt l lp 11 THPT, chng trnh Chun

    (Thi gian: 45 pht, 30 cu trc nghim)

    Phm vi kim tra: Chng 4. T trng; Chng 5. Cm ng in t

    Tn Ch Nhn bit(Cp 1)

    Thng hiu(Cp 2)

    Vn dng

    CngCp thp(Cp 3)

    Cp cao(Cp 4)

    Chng 4. Ttrng

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    1. T trng -Nu c t trng tn ti u v c tnh cht g.- Nu c cc c imca ng sc t ca thanhnam chm thng, ca nam

    chm ch U.(1 cu)

    -V c cc ng sct biu din v nu ccc im ca ng sct ca dng in thngdi, ca ng dy c dng

    in chy qua v ca ttrng u.(2cu )

    8 cu - 8/3

    2. Lc t.Cm ng t

    - Pht biu c nh nghav nu c phng, chiuca cm ng t ti mtim ca t trng. Nuc n v o cm ng t.- Vit c cng thc tnhlc t tc dng ln on dydn c dng in chy quat trong t trng u.

    (2 cu)

    - Xc nh c vect lc t tc dng ln mton dy dn thng c dng in chy qua ct trong t trng u.(3 cu)

    3. T trngca dng inchy trongdy dn chnh dng cbit

    - Vit c cng thc tnhcm ng t ti mt imtrong t trng gy bidng in thng di v hn.- Vit c cng thc tnhcm ng t ti mt imtrong lng ng dy c dng

    - Xc nh c ln,phng, chiu ca vectcm ng t ti mt imtrong t trng gy bidng in thng di.-Xc nh c ln,

    phng, chiu ca vect4 cu 4/3

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    in chy qua.

    (1 cu)

    cm ng t ti mt imtrong lng ng dy cdng in chy qua.

    (3 cu)4. Lc Lo-

    ren- x

    - Nu c lc Lo-ren-x l

    g v vit c cng thctnh lc ny.- Xc nh c cng ,

    phng, chiu ca lc Lo-ren-x tc dng ln mtin tch q chuyn ng vivn tc v trong mt phngvung gc vi cc ngsc ca t trng u.

    (3 cu)

    3 cu - 1

    S cu 15

    S im 5

    T l 50%

    S cu 7

    S im 2,3

    S cu: 8

    S im: 2,7

    S cu 15

    5,0 = 50%

    Chng 5. Cm ng in t1. TTHNG.CM NGIN T

    -Vit c cng thc tnht thng qua mt din tchv nu c n v o tthng. Nu c cc cchlm bin i t thng.

    - Lm c th nghimv hin tng cm ngin t.- Xc nh c chiuca dng in cm ng

    5cu 5/3

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    - M t c th nghim vhin tng cm ng in t.- Nu c dng in Fu-cl g.

    (3 cu)

    theo nh lut Len-x.

    (2 cu)

    2. SUTIN NGCM NG

    Pht biu c nh lut Fa-ra-y v cm ng in t.(2 cu)

    Tnh c sut inng cm ng trongtrng hp t thngqua mt mch bin iu theo thi giantrong cc bi ton:++

    (3 cu)

    5 cu - 5/3

    3. T CM Nu c t cm l g vn v o t cm.

    Nu c hin tng tcm l g.

    (2 cu)

    Tnh c sut inng t cm trong ng

    dy khi dng in chyqua n c cng bini u theo thi gian.

    Nu c t trngtrong lng ng dy cdng in chy qua vmi t trng u mangnng lng.

    5 cu - 5/3

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    (3 cu)

    S cu 15

    S im 5.

    T l 50%

    S cu: 7

    S im: 7/3

    S cu 8

    S im 8/3

    S cu 15

    5im=50%

    TS 30 s cu10(im)T l 100%

    14(14/3 )46 %

    16(16/3 )54 %

    30 (10)100 %

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    MA TRN KIM TRA HC K II(theo chng trnh chun)

    A. Bng trng s

    I- T lun

    Ch S tit L thuytS tit thc Trng s

    LT VD LT VD

    Chng IV. T trng 6 4 2,8 3,2 9 10

    Chng V. Cm ng in t 6 4 2,8 3,29 10

    Chng VI. Khc x nh sng 4 2 1,4 2,6 5 8

    Chng VII. Mt. Cc dng c quang 15 9 5,6 9,4 18 31

    Tng 31 19 12,6 18,4 41 59

    B. Tnh imII- T lun( 6 cu)Thi gian lm bi 45 pht

    Bng tnh im, tnh s cuCh s

    titL

    thuyts tit thc Trng s S cu im sLT VD LT VD LT VD LT VD

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    Chng IV. T trng 6 4 2,8 3,2 9 10 1 1,75Chng V. Cm ng in t 6 4 2,8 3,2 9 10 1 1,75Chng VI. Khc x nh sng 4 2 1,4 2,6 5 8 1 1,75Chng VII. Mt. Cc dng c quang 15 9 5,6 9,4 18 31 1 2 1,75 3

    Tng 31 19 12,6 18,4 41 59 2 4 3,5 6,5

    C. Thit k ma trn

    1. Ma trn cho t lun

    Tn ch Nhn bit(cp 1)

    Thng hiu(Cp 2)

    Vn dng CngCp 3 Cp 4

    Chng IV. T trng1. T trng 1. T trng l g? 1. Nu c t

    trng tn ti u v c tnh cht

    g.2. Nu c ccc im cang sc t cathnh nam chmthng v ca namchm ch U.

    1. V c cc ngsc t biu din vnu c cc c

    im ca ng sct ca dng inthng di v ca ngdy c dng inchy qua v ca ttrng u.

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    2. Lc t vcm ng t.

    1. Pht biu c nhngha cm ng t.2. c im vc t cmng t.

    1. Nm c quytc bn tay tridng xc nhchiu lc t. Vquy tc nm tay

    phi xc nhchiu ng sct.2. Vit c cngthc tnh lc t tcdng ln on dydn c dng inchy qua t trongt trng u.

    1. Xc nh c vect lc t tc dng lnmt on dy dnthng c dng inchy qua c t

    trong t trng u.

    1. Xc nh c lc ttng hp ti 1 im.2. Tm tp hp cc imm ti c lc t tnghp trit tiu.

    3. Cn bng ca mtdng in trong ttrng.

    3. T trngca dng inchy trong ccdy dn c hnhdng c bit.

    1. Vit c cng thctnh cm ng t ti mtim trong t trnggy ra bi dng inthng v di v hn.2. Vit c cng thctnh cm ng t ti mtim trong lng ng dyc dng in chy qua.

    1. Xc nh c ln, phng, chiuca vec t cm ng tti mt im trong ttrng gy ra bidng in thng di.2. Xc nh c ln, phng, chiuca vec t cm ng tti mt im tronglng ng dy c dngin chy qua.

    1. Xc nh c cmng t tng hp ti 1im.2. Tm tp hp cc imm ti c cm ngt tng hp trit tiu.

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    4. Lc Lo-ren-x

    1. Nu c lc Lo-ren-x l g v vit ccng thc tnh lc ny.

    1. S dng cquy tc bn taytri dng xcnh chiu lc Lo-ren-x.

    1. Xc nh ccng , phng,chiu ca lc Lo-ren-x tc dng ln mtin tch q chuyn

    ng vi vn tcv

    trong mt phngvung gc vi ccng sc t ca ttrng u.

    1. Gii c bi ton tl gia lc Lo-ren-xv vn tc ht.

    S cu

    T l

    1 cu ( 1,75 im) = 16,7% 1 cu(1,75 im)

    = 16,7%Chng V. Cm ng in t

    1. Sut inng cm ng

    1. Pht biu c nhlut Fa-ra-y v cmng in t. Biu thc.

    1. Tnh c sutin ng cm ngtrong trng hp tthng qua mch bini u theo thi giantrong cc bi ton.

    2. Sut inng cm ng 1. Pht biu c nhlut Fa-ra-y v cmng in t. Biu thc.

    1. Tnh c sutin ng cm ngtrong trng hp tthng qua mch bini u theo thi giantrong cc bi ton.

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    3. T cm 1. Nu c t cml g v n v o tcm.2. Nu c hin tngt cm l g.3. Nu c t trngtrong lng ng dy cdng in chy qua vmi t trng u mangnng lng.

    1. Tnh c sutin ng t cmtrong ng dy khidng in chy quan c cng bini u theo thigian.

    S cu

    T l

    1 cu ( 1,75 im) = 16,7% 1 cu( 1,75 im)

    = 16,7%Chng VI. Khc x nh sng

    7. Khc xnh sng

    1. Nu c hin tngkhc x. V d.2. Bit tia sng tuynthng v ch b lch khitruyn xin gc qua haimi trng trong sutkhc nhau.

    3. Hiu s lin quangia chit sut v tc truyn nh sng trongcc mi trng.4. Pht biu c nhlut khc x nh sng vvit c h thc canh lut ny.

    1. Nu n21 > 1 th r< i v n21 < 1 th r> i2. V c ngi tia sng thunv nghch.3. Phn tch c

    hnh v v tiakhc x v thitlp c mi quanh gia gc ti,gc khc x cngnh chit sut cahai mi trng.4. Bit c mi

    1. Bit tnh chit sut,gc ti, gc khc xtrong cc h thc canh lut khc x.2. Tnh c vn tcca tia sng khi iqua cc mi trng

    trong sut khc nhau.3. Gii thch c vsao mt ngi quanst thy mi vt xungquanh. ra phng

    php tng hnh .

    (Ch xt bi ton c

    1. Gii c bi tonlp t l chit sut giacc mi trng.2. Vn dng cng thcnh lut khc x kthp vi kin thc tonhc nh tam gic ng

    dng, tam gic vung tm su mc chtlng da vo khc x.

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    5. Bit c cc khinim: tia ti, tia khc x,tia phn x cng nhgc ti, gc khc x vgc phn x, chit sut,chit sut t i, chitsut tuyt i.6. Nu c tnh chtthun nghch ca struyn nh sng v ch ras th hin tnh cht ny nh lut khc x nhsng.

    lin quan gia gcti v gc khcx. Cng nh sinca n.

    ti a hai ln khc xca tia sng trn mtng truyn).

    2. Phn x

    ton phn

    1. M t c hin

    tng phn x tonphn.2. Nu c 2 iu kin c phn x ton phn,

    biu thc.

    1. Bit nhn dng

    cc trng hpxy ra hin tngphn x ton phnca tia sng khiqua mt phncch.2. Hiu cnguyn tc cu toca cp quang,

    phng php nisoi, truyn dn tnhiu (thng tin).Cp quang c uim hn so vicp kim loi ltruyn c lngd liu rt ln,

    1. Bit dng iu kin

    xy ra phn x tonphn xc nh cctrng hp xy ra

    phn x ton phn khitia sng i qua mt

    phn cch cc mitrng trong sut.

    1. Gii c bi ton

    v phn x ton phnkt hp vi hnh hc(o bng , gc giihn nh nht bao nhiu khng c khcx,...).

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    khng b nhiu bitrng in t bnngoi.3. Gii thch chin tng o nh.4. Nguyn tc tnghnh.

    S cu

    T l

    1 cu ( 1,75 im) = 16,7% 1 cu(1,75 im)= 16,7%

    Chng VII. Mt. Cc dng c quang

    1. Lng knh 1. Lng knh l g? Nuc tnh cht ca lngknh lm lch tia sngtruyn qua n.2. Nm c cc khinim: gc ti, gc l,gc lch, gc khc x,gc chit quang, tia ti,tia l, tia khc x.3. V c ng

    truyn tia sng qua lngknh.

    1. V c tiasng qua lngknh.

    1. Vn dng c cccng thc ca lngknh tm gc l,gc lch v chitsut.

    1. Bi ton iu kin c tia l v khng c tial qua lng knh.

    3 cu

    2. Thu knhmng.

    1. Nu c cc khinim: Thu knh mng,cc loi thu knh, trcchnh, trc ph, quangtm, tiu im vt chnhF, tiu im nh chnh

    1. Nm c ccquy tc tia sngqua tiu im F,F, F1, F2... vc ngtruyn tia sng qua

    1. Vn dng cc cngthc v thu knh gii c cc bi tpn gin:-Tm v tr vt, nh(da trn tiu c f v

    1. Bi ton v s dichuyn ca thu knh,vt v nh.2. Thu knh ghp.

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    F, tiu im vt ph F1,tiu im nh ph F1.Tiu din, tiu c f,khong cch t vt tithu knh d v khongcch t nh ti thu knhd.2. Nm c cc cngthc tm v tr vt, nh:

    d.d '

    'f

    d d=

    +

    '.

    '

    d fd

    d f=

    .'

    d fd

    d f=

    3. Nu c nh ngha

    t v biu thc:1D

    f= (lu i n v

    f)4. Nu c nh nghas phng i ca nh to

    bi thu knh?'d

    kd

    =

    5. Nm c quy c v

    du ca f, d, d, k.

    thu knh hi t,phn k v h haithu knh ngtrc.

    da trn khong cchca vt v nh L hoc phng i k)2. Dng c nh cavt l im sng Shoc l vt phng nhAB vung gc vitrc chnh ca thuknh qua thu knh hit hay phn k.3. S quy tc 3 imthng hng O, S, Shoc M, S, F dng v xc nh loi

    thu knh.

    ( 5,25 im)

    3. Mt 1. Bit c cu to camt.2. im cc vin, imcc cn.3. Nng sut phn li camt.4. Cc tt ca mt v

    1. Nu c siu tit ca mtkhi nhn vt im cc cn v im cc vin.2. Nu c gctrng v nng sut

    1. Bi ton sa tt mtcn th v vin th.2. Bi ton xc nhim cc cn v imcc vin.3. Phm vi t vt khikhng eo knh.

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    cch khc phc. phn li l g.3. Trnh by ccc im ca mtcn, mt vin, mtlo v mt quanghc v nu tcdng ca knh cneo khc phccc tt ny.4. Nu c slu nh trn mngli l g v nuc v d thc tng dng hin

    tng ny.4. Knh lp 1. Bit k hiu 3x, 5x,8x... ghi trn knh lp.2. Bit khi nim gctrng nh v gc trngvt.

    1. Nu cnguyn tc cu tov cng dng caknh lp.2. Trnh by cs bi gic canh to bi knhlp.

    3. Cch ngmchng v cc vngm chng im cc cn.

    1. V c nh cavt tht to bi knhlp v gii thch tcdng tng gc trngnh ca knh.

    1. Xc nh phm vingm chng mt vtqua knh lp.2.Tm s bi gic.

    5. Knh hin vi 1. Bit khi nim vtknh v th knh, diquang hc ca knh hinvi.

    1. Nu cnguyn tc cu tov cng dng caknh hin vi.

    1. V c nh cavt tht to bi knhhin vi v gii thchtc dng tng gc

    1. Xc nh phm vingm chng mt vtqua knh hin vi.2.Tm s bi gic.

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    2. Trnh by cs bi gic canh to bi knhhin vi.

    trng nh ca knh.

    6. Knh thinvn

    1. Bit khi nim vtknh v th knh ca knhhin vi.

    1. Nu cnguyn tc cu tov cng dng caknh thin vn.2. Trnh by cs bi gic canh to bi knhthin vn l g.

    1. V c nh cavt tht c to biknh thin vn v giithch tc dng tnggc trong nh caknh

    1. Xc nh phm vingm chng mt vtqua knh hin thin vn.2.Tm s bi gic.

    7. Thc hnh 1. Xc nh c tiuc ca thu knh phn

    k bng th nghim.S cu

    T l

    1 cu ( 1,75 im) = 16,7% 2 cu ( 3,5im) = 33%

    Tng s cu

    T l

    2 cu ( 3,5 im) = 33% 4 cu ( 6,5 im) = 67% 6 cu( 10 im)

    100%

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