Algebra
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Transcript of Algebra
Ley absorbente del cero y neutralidad del 1
a · 0 = 0 1 · a = a
Distribuciones
− (a± b) = −a∓ b a (b + c) = ab + ac
a (b + c) (d + e) = abd + abe + acd + ace (a + b) (c + d) = ac + ad + bc + bd
− (−a) = a
Inversos multiplicativos...Fracciones
0
a= 0, a 6= 0
a
1= a
a
a= 1
(ab
)−1=
1ab
=b
a(ab
)−c=
((ab
)−1)c
=
(b
a
)c −a−b
=a
b
a−b =1
ab−a−b
=a
b−ab
= −a
b
a
−b= −a
b
−ab
= −a
b
bc
a=
b
c · a1bc
=c
b
Valor Absoluto
|−a| = a |a| = a , a ≥ 0
|−a| = |a| |ax| = a |x| , a ≥ 0
Reglas de Exponentes
1a = 1 a1 = a
a0 = 1 , a 6= 0 0a = 0 , a 6= 0
(ab)n = anbnam
an= am−n , m > n(
ab)c
= ab·c(ab)c
= ab·c(ab
)c=
ac
bca
mn =
(n√a)m
ac · bc = (a · b)c n√a · b = n
√a
n√b
1
Formulas Notables
x2 − y2 = (x− y) (x + y)
x3 + y3 = (x + y)(x2 − xy + y2
)4
xn − yn = (x− y)(xn−1 + xn−2y + · · ·+ xyn−2 + yn−1
)xn + yn = (x + y)
(xn−1 − xn−2y + · · · − xyn−2 + yn−1
)ax(2n) − b =
(√axn +
√b)(√
axn −√b)
ax4 − b =(√
ax2 +√b)(√
ax2 −√b)
ax(2n) − by(2m) =(√
axn +√bym
)(√axn −
√bym
)ax4 − by4 =
(√ax2 +
√by2
)(√ax2 −
√by2
)Reglas Logarítmicas
log (0) = −∞ log (1) = 0
loga (a) = 1 loga
(xb)
= b · loga (x)
logab (x) =1
bloga (x) loga
(1
x
)= − loga (x)
log 1a
(x) = − loga (x) logxn (x) =1
n
loga (b) =ln (b)
ln (a)logx (xn) = n
logx
((1
x
)n)= −n aloga(b) = b
In-de�niciones
00 = indefinidox
0= indefinido
loga (b) = indefinido , a < 0 loga (b) = indefinido , b < 0
log1 (a) = indefinido log0 (a) = indefinido
Números que no pertenecen a R
i2 = −1√−1 = i
√−a =
√−1√a
2