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agust,www,...januar09/Profun-080209ak.ppt. 4). 2). 3). 1). 1) Ed(0), J´= 0 – EVv´=8,J´= 0 = 45.553 cm-1. 2) EVv´=9, J´= 5 – EDv´=0,J´= 5 = 164.24 cm-1. 3) Ef(2), J´= 5 – EVv´=8,J´= 5 = 17.14 cm-1. 4) EVv=10, J´= 3 – Egv=0 J´= 3 = 106.64 cm-1. - PowerPoint PPT Presentation

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84x103

83

82

81

2 h

[cm

-1]

g3-

(0+),v'=0

V1+

, v'=9

V1+

, v'=10

0

1

1

2

4f3

1(v´=0)

f3

2(v´=0)

f3

3(v´=0)

V1+

, v'=8

V1+

, v'=7

3

C1(v´=1)

D1(v´=0)

F1(v´=0)

d3(v´=0)

d3(v´=0)

g3-

(1),v'=0

E1+

,v'=0

1)

1) Ed(0), J´=0 – EVv´=8,J´=0 = 45.553 cm-1

3)

3) Ef(2), J´=5 – EVv´=8,J´=5 = 17.14 cm-12) EVv´=9, J´=5 – EDv´=0,J´=5 = 164.24 cm-1

2)

4)

4) EVv=10, J´=3 – Egv=0 J´=3 = 106.64 cm-1

agust,heima,...january09/Profun-080209ak.pxp <= agust, heima, ...january09Term values for triplet paper-080209kmak.xls